Thermo dynamics, energy calculations in a duct

AI Thread Summary
The discussion focuses on energy calculations for a duct carrying a heavy gas, detailing the changes in internal energy, enthalpy, and flow energy. The internal energy was calculated to be 72,960 J, enthalpy at 88,400 J, and flow energy at 15,440 J. The challenge lies in determining kinetic energy, which requires calculating the velocity of the gas. To find the velocity, the mass flow rate must be set equal to the product of density, cross-sectional area, and velocity, using the ideal gas law to determine density. The calculations aim to understand energy transformations as the gas flows through the duct and into a divergent pipe section.
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Homework Statement



A duct of length 5 m at 38 Degrees inclination to horizon with a cross section dimensions of 0.3 m X 0.4 m is carrying 2 kg/s of a heavy gas at 10C and 1.2 bars and delivers the gas flow at 50C at the end of the duct to a horizontal pipe section. i) Calculate changes to all the individual forms of energy being transported in the DUCT, if Cp and Cv of the gas are 1105 J/kgK and 912 J/kgK. The horizontal section of the pipe is a divergent section with exit cross section area of 0.24 m2. ii) Calculate the mass flow rate at the exit of the divergent pipe and the speed of the flow assuming temperature remains at 50C.

Homework Equations


not a clue


The Attempt at a Solution


found internal energy to be 72960j
found enthalpy to be 88400j
work done or flow enrgy to be 15440
cant work out kinetic energy as cannot work out the velocity
 
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To get the velocity, set the mass flow equal to rho*A*V where rho is density, A is area, and V is velocity. Determine rho from ideal gas law. The mass flow does not change so the product of rho, A, and V is constant.
 
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