Thermochemistry: Understanding Delta H and Work in Constant Pressure Reactions

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In a discussion on thermochemistry, a user seeks to calculate delta H for a reaction at constant pressure, given delta U of -72 KJ and 39 KJ of expansion work. Confusion arises regarding the meaning of delta U and its representation in formulas, with some sources using U and others using E interchangeably. The correct relationship is established as delta H equals delta U plus P delta V. The user speculates that delta H might be -111 KJ but seeks confirmation on the definitions. Ultimately, the conversation clarifies that delta U and delta E are equivalent, aiding in the understanding of the calculations.
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1. For a certain reaction at constant pressure, delta U= -72 KJ, and 39KJ of expansion work is done by the system. What is delta H for this process.

2. I basically have no idea what to do because it's not in my textbook and my professor has never taught this. Maybe If I knew what the delta U stood for I could understand it.

Thanks

Edit: Wild guess, answer is -111 KJ?
 
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Anybody know what the damn delta U supposed to signify
 
No, It does not. In my book this is the only way this is written \Delta{H}\,=\,\Delta{E}\,+\,P\Delta{V} My guess was that it stood for E but i wasnt sure. Does that I am right?
 
ace123 said:
No, It does not. In my book this is the only way this is written \Delta{H}\,=\,\Delta{E}\,+\,P\Delta{V} My guess was that it stood for E but i wasnt sure. Does that I am right?

yes, some places use U and some use E, they are the same
 
Okay, Thanks

Edit: Are you stalking my posts eli64 :smile:
 
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