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Thermocouple homework

  1. Dec 4, 2007 #1
    1. The problem statement, all variables and given/known data

    The one end of the thermocouple is placed in 45C water, the other end in oil of unknown temperature. Of the voltmeter connected to it's end I got 1.35mV. If the sensitivity of the thermocouple is 0.05mV/C, what will the difference of temperature of the liquids be?

    2. Relevant equations

    This is really what I'm looking for. Not sure at all what equation I would use.

    3. The attempt at a solution

    Would doing something like:
    1.35mV / 0.05mV/C = 27C
    Would 27C be the difference

    Thanks for any input
  2. jcsd
  3. Dec 7, 2007 #2

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    I don't see what else could it be. What does your text book say?
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