Ideal gas law:
Workdone by the gas:
For Isobaric process
For Isothermal Process
The Attempt at a Solution
subpart (a) is trivial, all we have to do is to substitute the given data in Ideal gas law to get the temperatures.
I have conceptual difficulty in part (b) and (c)only
The PV diagram conists of two Isothersms (DA and BC) and two Isobars (AB and CD)
How to calculate workdone by the gas?
Is it just the sum of the workdone by four processes ?
Next, Heat absorbed by gas?
Since the total Internal energy U of a cyclic process is zero, is it just equal to the total workdone?
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