Thermodynamic/Carnot efficiency

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A novel heat engine is being evaluated for harnessing thermal energy from wastewater at a food processing plant, with wastewater at 35°C and an ocean temperature of 10°C. The maximum power output can be calculated using the Carnot efficiency formula, which yields an efficiency of 8%. The flow rate of the wastewater is 1,000 gallons per minute, equivalent to 63.09 kg per second. To find the maximum power, the total heat (Q) must be calculated using the heat capacity of water and the temperature difference, followed by determining work (W) and power (P) based on the chosen time interval. The discussion highlights the importance of correctly applying thermodynamic equations to derive the desired results.
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Homework Statement



A novel heat engine is being considered for producing work from the thermal energy contained in the wastewater discharge from a large food processing plant. On an average day, 35 degree celcius wastewater leaves the plant at and is discharged into the ocean at 1,000 gallons PER minute. if the average annual ocean temperature is 10 degree celcius at that location, what is the maximum power that could be produced by this heat engine? What would be the thermal cycle efficiency of your maximum power engine? You can assume that the heat capacity of water at constant pressure is contant at 4,200 J/Kg K.


Homework Equations



delta T = Tf - Ti
Q = mc delta T
Carnot n=1-(Tc/Th)
W= total heat times Carnot n
P=W/t

The Attempt at a Solution



1000 Gallons per minute = 63.09 Kg per sec

T1 = 10 +273 = 283K
T2 = 35 +273 = 308K
Delta T = 25 K
Carnot η = 1- 283K/308K = 0.08 = 8%
How can I calculate the maximum power with the rate flow and without the time? I think i am missing an equation.
 
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You can choose a convenient time. Since you calculated the rate in kg/s, you have t and m. You can then determine Q (Total Heat), since you have C (Heat Capacity) as a given, and you calculated m/t and you have T. Once you have Q, you can calculate W and then P, using the same t that you chose earlier.
 
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