Thermodynamics Cubes of Metal Problem

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Homework Help Overview

The problem involves three cubes made of lead, iron, and copper arranged between two heat boxes at different temperatures (100°C and 0°C). The heat current between the boxes is given as 155W, and the task is to determine the side length of the cubes and the temperature between the lead and iron cubes.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply the heat transfer equation but is uncertain about how to isolate the side length without knowing the temperatures. Another participant introduces the concept of effective thermal conductivity (keff) and suggests a method to find it using the thermal conductivities of the individual materials.

Discussion Status

The discussion is ongoing, with participants exploring the definitions and implications of effective thermal conductivity. Some guidance has been provided regarding the relationship between the materials' thermal conductivities and the overall heat transfer, but there is no explicit consensus on the next steps or final approach.

Contextual Notes

Participants are working under the constraints of the problem statement and are seeking clarification on terms and concepts related to thermal conductivity. There is a noted lack of clarity regarding the effective thermal conductivity and its application in this context.

mneox
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Homework Statement



Three cubes of equal lengths, lead, iron, and copper are arranged between heat boxes at 100C and 0C. The heat current between boxes is 155W.

1) What is the side length of the cube?
2) What is the temperature between the lead and iron cubes?

Some k values are also given for the materials.

I know that we have to use H = [kA (T2-T1)] / L and the teacher partially explained it but moved along too fast for me to catch.

Homework Equations



H = [kA (T2-T1)] / L

The Attempt at a Solution



I realize that since it's a cube, A = L^2.

So therefore:

H = k L (100 - T1) = k L (T1 - T2) = k L (T2 - 0)

And then I get stuck because I want to find L, but my temperatures are still unknown. Isn't there some way to find the length without the temperature? Thank you for any help!
 
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[tex]H = \frac{kA(T_2 - T_1)}{L}[/tex]

In the given problem, it becomes

[tex]H = \frac{k_{eff}.L^2(T_2 - T_1)}{3L}[/tex]

[tex]H = \frac{k_{eff}.L(T_2 - T_1)}{3}[/tex]...(1)

If A1 = A2 = A3 = A and L1 = L2 = L3 = L

[tex]\frac{3}{k_{eff}} = \frac{1}{k_1} + \frac{1}{k_2} + \frac{1}{k_3}[/tex]

Find keff, and substitute in equation 1 and solve for L.
 
Thanks for your reply.. but what is keff??

(Not the value, but what does it stand for?)
 
mneox said:
Thanks for your reply.. but what is keff??

(Not the value, but what does it stand for?)
It is the effective thermal conductivity. If you have a single block of same dimension instead of three different blocks, what would be its thermal conductivity to have the same rate of energy flow.
 

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