Thermodynamics/Entropy Question

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To calculate the increase in entropy for the parachutist, the work done during descent can be determined using the equation W = mgh, resulting in 281,547 J. The relevant entropy equation S = Q/T requires knowledge of the heat transfer and temperatures involved. The body temperature can be assumed to be 37 degrees C, but clarification on whether this is necessary is sought. The challenge lies in converting work into useful heat transfer values for further calculations. Guidance on these aspects is requested to solve the problem effectively.
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Homework Statement


An 82-kg parachutist descends through a vertical height of 350 m with constant speed. Find the increase in entropy produced by the parachutist, assuming air temperature of 21 degrees C.

2. Relevant Equation
S = Q/T

The Attempt at a Solution


I believe I can find work via W = mgh or (82)(9.81)(350) = 281,547 J. What can I do from there.

Thanks in advance.
 
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Can I assume the body temperature is 37 degrees C? Do I need to? I cannot figure out how to find hot temperature and heat transfered. Are there any ideas on how I can convert W in this situation into something useful to further the problem? Any hints towards the right direction would be appreciated.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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