Solving a Thermodynamics Problem: Finding ΔHf for OH(g) in H2O2 (g) Reaction

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To find the standard enthalpy of formation (ΔHf) for OH(g) in the reaction H2O2(g) → 2OH(g), the ΔH(diss) of 213 kJ/mol represents the enthalpy change for the dissociation of hydrogen peroxide. The relationship between ΔH(diss) and ΔHf indicates that ΔH(diss) equals twice the ΔHf of OH(g). To solve for ΔHf, one must use the enthalpy of reaction formula, which is the difference between the enthalpy of formation of products and reactants. This requires looking up the enthalpy of formation for H2O2 and substituting the values into the equation. Ultimately, this approach will yield the desired ΔHf for OH(g).
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How do i solve this chem, thermodynamics problem?
find ΔHf for OH(g) if

H2O2 (g)--> 2OH(g)

ΔH(diss)=213KJ/mol

what is ΔH(diss)?? what is 'diss'

someone told me The ΔH(diss)=213KJ/mol is equal to twice the ΔHf of OH. but i doont know how they got to this, also it seems a bit too simple for a qestion if all i need to do is divide by 2,
so how would i solve this?
 
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Your \Delta H(diss) is your enthalpy of reaction. Remember that the enthalpy of reaction equals: Enthalpy of formation of products - Enthalpy of formation of reactants. Replace your data (you will need to look for H2O2 enthalpy of formation on a table) there and solve for \Delta H(OH).
 
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