[thermodynamics] rate of ice formation, -area, +density

In summary, the problem involves calculating the rate of ice formation on a tank of water that has been exposed to cold weather. Given the air temperature above the ice slab and the thermal conductivity and density of ice, the rate can be determined using equations involving thermal conductivity, density, and heat of transformation. By relating the density to the rate of ice formation, it is possible to calculate the area of the ice slab and ultimately determine the rate of ice formation in cm/h.
  • #1
fancyterm
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Homework Statement



A tank of water has been outdoors in cold weather, and a slab of ice 5 cm thick has formed on its surface. The air above the ice is -10C. Calculate the rate of ice formation ( in cm / h) on the ice slab. Take the thermal conductivity of ice to be 0.004 cal / (s.cm.C) and its density to be 0.92 g/cm^3. Assume no energy transfer through the tank walls or bottom.

Homework Equations



P(conducted) = Q/t = kA (T2-T1)/ Length
p(density) = m/v
Q = Lm heat of transformation

The Attempt at a Solution



Some thoughts:
When they say on the slab, they must mean underneath it right?
Also they provide standard info the in the question like the conductivity of ice which I could look up in a table. I could similarly look up density and conductivity of water but since they didnt explicidly mention that too, I wonder if I'm not supposed to? Like maybe that's variable in terms of the problem?
Since they arent just asking the rate of conductivity through ice I probably need to use the heat of fusion formulae somewhere too.

So I need to relate the density somehow, in order to cancel out the Area which I don't have.

Pluggin in info for the conduction rate equation I get
P = 0.004A (0--10) / 5
P = A x 0.008

now for density
p = m/v = m/Ah (using A and h because I have more information about that, than just V)
0.92 = mA5

I don't see an obvious relation.
(heat of fusion from water to ice = 333)

Q = Lm
Q = 333m
Q = 333 x 0.92/5A

Uhm I don't know where I am going with this. I could say both equations are equal to A, but then I still have P and m as variables
 
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  • #2
You're relating density to the current thickness of the slab, but don't you want to relate it to the ice growth rate (i.e., connect a cm/h rate to a g/s rate)?
 
  • #3
But the density of the ice doesn't change as more is added to it, does it? The ice formed already keeps its density and as for the ice busy forming - isn't each bit formed instantly at its maximum density?
 
  • #4
I don't mean that the density is variable; I mean that you've written an equation equating the ice density to the ratio of the original slab mass and the original slab volume (which is valid but irrelevant), but what you want to do is write an equation equating the ice density to the ratio of the rate of increasing ice mass and the rate of increasing ice volume.
 
  • #5
Hey, I know this post is old, but i find myself working over a close to identical problem and find myself in the same situation. I can't figure out how to get the area from the density. I have an expression Pcont = .008A and I know that density is mass over volume. However, I also know it is constant in the Ice. I have no expression for mass. The only thing I need to get is the rate of the formation of ice, which should be equal to Pcont. I just can't find an expression to manipulate the density to get the Area. The correct answer is .4 cm/s
 
  • #6
Hi blackstrat, welcome to PF.

If you know the mass rate of ice formation (in kg/s) and you know the ice density (in kg/m^3), then you can easily find the volume rate of ice formation (in m^3/s). Know what I mean?
 
  • #7
Recived the same homework and solved as follows:
P=kA ∆T/L
Q/t=kA ∆T/L
Q_1=t.kA ∆T/L=3600 .0,004 .2A=28,8cal/〖cm〗^2
Q_2=L .m=333kJ/kg=79,55cal/g
p=m/v=0,92g/〖cm〗^3
∴Q_2=73,19cal/〖cm〗^3 (substitute density intoheat of transformation)
but Q_1=Q_2 so then cm=28,8/79,55=0,4cm
 

Related to [thermodynamics] rate of ice formation, -area, +density

What is the rate of ice formation?

The rate of ice formation refers to how quickly water molecules freeze and form ice crystals. This rate is affected by factors such as temperature, pressure, and the presence of impurities.

How does the area affect the rate of ice formation?

The area of a surface can affect the rate of ice formation by providing more space for ice crystals to form. A larger surface area can also allow for more heat transfer, which can speed up the rate of ice formation.

Does density play a role in the rate of ice formation?

Density can impact the rate of ice formation by affecting the movement of water molecules. In general, denser liquids freeze at a slower rate than less dense liquids.

What factors can influence the rate of ice formation?

The rate of ice formation can be influenced by a variety of factors including temperature, pressure, surface area, and the presence of impurities. Other factors such as air flow and the presence of nucleation sites can also impact the rate of ice formation.

How is the rate of ice formation measured?

The rate of ice formation can be measured using various methods, such as monitoring changes in temperature or recording the growth of ice crystals over time. Scientists also use mathematical models and simulations to study and predict the rate of ice formation under different conditions.

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