Thermodynamics resistance temperature scale

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SUMMARY

The discussion centers on the resistance temperature scale, specifically addressing an error in the homework statement regarding the temperature units. The equation R=Ro(1 +αt+βt²) is used, where α and β are defined in Celsius units, not Kelvin. Participants clarify that the constants α and β should be expressed in Celsius^-1 and Celsius^-2, respectively, to align with the temperature scale required for the problem. The main goal is to find the ideal gas temperature equivalent using the resistance scale, emphasizing the need for correct unit conversion.

PREREQUISITES
  • Understanding of resistance temperature relationships
  • Familiarity with the equation R=Ro(1 +αt+βt²)
  • Knowledge of temperature scales, specifically Celsius and Kelvin
  • Basic algebra for isolating variables in equations
NEXT STEPS
  • Research the derivation and application of the resistance temperature equation R=Ro(1 +αt+βt²)
  • Study the differences between Celsius and Kelvin temperature scales
  • Explore the concept of temperature correction factors in thermodynamics
  • Learn about the ideal gas law and its relationship to temperature measurements
USEFUL FOR

Students studying thermodynamics, physics educators, and anyone involved in temperature measurement and calibration using resistance methods.

jeremyskate
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Homework Statement


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IMPORTANT:There is an error in the statement.α and β are in C not K

2. Homework Equations

R=Ro(1 +αt+βt2)

The Attempt at a Solution


I really don't know what to do because if I isolate t in the equation it will give me the temperature on the ideal gas scale whereas the temperature I need to find is on the resistance scale.
 
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Re-read the problem statement: where is "K" used? What does the "correction" imply should be used instead?
 
The temperature is in celsius degrees not kelvin so the constant α is in celsius^-1 and β in celsius^-2 in order to negate t and t^2. This is a correction our teacher made after giving us the statement. Is that what you were celsius to?
 
Yes.
 
Are you saying I simply need to solve R for the given conditions? Because that would give me a value of resistance not temperature and the exersice is to find the ideal gas temperature equivalent on the resistance scale.
 

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