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Thermodynamics - Time

  1. Apr 12, 2010 #1
    1. The problem statement, all variables and given/known data
    A 5.0-m-diameter garden pond is 0.200 m deep. Solar energy is incident on the pond at an average rate of 400 W/m^2 . If the water absorbs all the solar energy and does not exchange energy with its surroundings, how many hours will it take to warm from 16.0C to 20.0C?


    2. Relevant equations
    I'm have been using the equation Q/t = e * (5.67 * 10 ^ -11) * A *T^4
    Not sure if this is correct.


    3. The attempt at a solution
    My lesser attempts assigned the radiated power to Q and I would solve for time, however I am pretty sure this is incorrect.
     
  2. jcsd
  3. Apr 12, 2010 #2

    Andrew Mason

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    Homework Helper

    This is a heat capacity question, not a radiation question. Use:

    [tex]Q = mC\Delta T[/tex]

    where Q = Power x time

    Hint: you have to work out the mass of the water in the pond and the rate at which solar heat energy is added to the pond.

    AM
     
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