Calculate entropy change if two equal volumes of gas (1 cm3) at standard temperature and pressure are separated from each other by a partition which is removed to create twice the volume at standard temperature and pressure
dS = k.N. dV/V + C/T dT
P1V1 = P2V2
The Attempt at a Solution
Im making the assumption that the two gases are not ideal, this question leads on to an essay on the gibbs paradox and i believe the correct anser should be zero entropy change.
Im struggling to prove this though as the pressure must stay the same before and after, if the pressure stays the same then due to boyles law the volume must stay the same, but in the question it ofcourse states the volume increases to twice its origninal value.
Im sure i must be missing something here?