Thickness of film when you are given indexes of refraction. HELP

AI Thread Summary
To determine the thickness of a film that creates strong reflections for 610 nm light, one must consider the principles of thin film interference. The initial condition involves a film of index 1.7 coated on a glass lens with an index of 1.6, where the thinnest film results in constructive interference. As the film thickness increases, strong reflections will occur again at specific thickness values that correspond to additional constructive interference conditions. The key is to apply the interference equations for thin films, accounting for the phase change upon reflection. Understanding these concepts will guide the calculation of the required film thickness.
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Homework Statement



You are coating a glass lens of index of refraction 1.6 with a film of material of index of refraction 1.7. You start with the thinnest film possible that creates a strong reflection for 610 nm light. You gradually increase the film thickness until you again get strong reflection. What is the thickness of the film now?



Homework Equations


Not sure where to even start. Any help would be nice!


The Attempt at a Solution


Just need to be pointed in the right direction please!
 
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Think of interference on thin films.

ehild
 
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