This is seems like an easy question

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The discussion revolves around calculating the change in potential energy for a particle acted upon by a conservative force described by the equation Fx = (2x + 4) N. The user initially assumes that potential energy is zero since the motion is horizontal, but this assumption is incorrect. It is suggested that the user should apply the work-energy principle, where the work done by the conservative force relates to the change in potential energy (W = -ΔU). The conversation emphasizes the importance of using the correct equations to find the potential energy change as the particle moves along the x-axis. Understanding these concepts is crucial for solving the problem accurately.
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This is seems like an easy question...

Homework Statement


A single conservative force acts on a 5.00 kg particle. The equation Fx = (2x + 4) N describes this force, where x is in meters. As the particle moves along the x-axis from x = 2.20 m to x = 6.60 m.

Calculate the change in the potential energy of the system

Homework Equations


The Attempt at a Solution



Since it just only involves horizontally, I thought the Potential Energy would be zero, but it's telling me it's wrong.

?
 
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I think you should look up relevant equations, like how work done by a conservative force F will be W = -ΔU where ΔU is the change in the potential energy. So W = Fd (force*distance) or W = Fdcosθ...
 
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