This is seems like an easy question

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SUMMARY

The discussion centers on calculating the change in potential energy for a 5.00 kg particle subjected to a conservative force defined by the equation Fx = (2x + 4) N, as it moves from x = 2.20 m to x = 6.60 m. Participants clarify that the potential energy is not zero despite the horizontal movement, emphasizing the relationship between work done by a conservative force and potential energy change. The correct approach involves using the work-energy principle, specifically W = -ΔU, where W is the work done by the force over the distance traveled.

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This is seems like an easy question...

Homework Statement


A single conservative force acts on a 5.00 kg particle. The equation Fx = (2x + 4) N describes this force, where x is in meters. As the particle moves along the x-axis from x = 2.20 m to x = 6.60 m.

Calculate the change in the potential energy of the system

Homework Equations


The Attempt at a Solution



Since it just only involves horizontally, I thought the Potential Energy would be zero, but it's telling me it's wrong.

?
 
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I think you should look up relevant equations, like how work done by a conservative force F will be W = -ΔU where ΔU is the change in the potential energy. So W = Fd (force*distance) or W = Fdcosθ...
 

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