Kawada
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In theory this is a simpel integral problem which i can't solve
So I'm doing some plasma physics, and it comes with the derivation of the Thompson scattering (please bear with the first time I've tried using latex, I am sorry some of the greek lowercase laters look like superscripts, there not supposed to)
So I'm at the point where i have the total cross-section \sigmaT = the integral of (d\sigma/d\Omega) d\Omega.
ok so I've been given (d\sigma/d\Omega) = re2sin2\thetaso the integral d\Omega = d\thetad\phi, with \theta between 0 and pi, and \phi between 0 and 2pi.
but so the \phi integral just gives 2pi, and in my attempt the integral of sin2\theta with respect to \theta over 0 and pi, is just pi/2?
yet looking at my notes, and the actual thompson scattering they have \sigmaT = 8pi*re2/3
now in my notes it says that the ingtegral over sin2\theta d\theta can become the integral over -sin2\theta dcos\theta still with \theta between 0 and pi, and this yes, gives the required answer of 8pire2/3.
but hows do they change the intergral to that?
that is my only qualm, how they change the integral, and how my method of just ingetraing sin2\theta d\theta is not just pi/2?
i appreciate any help! :D (sorry for the long explanation)
So I'm doing some plasma physics, and it comes with the derivation of the Thompson scattering (please bear with the first time I've tried using latex, I am sorry some of the greek lowercase laters look like superscripts, there not supposed to)
So I'm at the point where i have the total cross-section \sigmaT = the integral of (d\sigma/d\Omega) d\Omega.
ok so I've been given (d\sigma/d\Omega) = re2sin2\thetaso the integral d\Omega = d\thetad\phi, with \theta between 0 and pi, and \phi between 0 and 2pi.
but so the \phi integral just gives 2pi, and in my attempt the integral of sin2\theta with respect to \theta over 0 and pi, is just pi/2?
yet looking at my notes, and the actual thompson scattering they have \sigmaT = 8pi*re2/3
now in my notes it says that the ingtegral over sin2\theta d\theta can become the integral over -sin2\theta dcos\theta still with \theta between 0 and pi, and this yes, gives the required answer of 8pire2/3.
but hows do they change the intergral to that?
that is my only qualm, how they change the integral, and how my method of just ingetraing sin2\theta d\theta is not just pi/2?
i appreciate any help! :D (sorry for the long explanation)