Thompson's Absolute Electrometer

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X53
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Suppose that the force needed to push a disc down on top of another disk = weight x g, then the two discs are charged with opposite quantities of electricity, then the weight removed, and still the discs remain together due to the force of attraction between the discs; so then the electric force between them is equal to the force from the weight, right? this implies that Wg = (V^2A)/[(8PI)D^2], V is voltage, A is the area of the top disc, D is the distance between them: How to explain the equation? what is the significance of 8pi?
 
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X53 said:
Suppose that the force needed to push a disc down on top of another disk = weight x g, then the two discs are charged with opposite quantities of electricity, then the weight removed, and still the discs remain together due to the force of attraction between the discs; so then the electric force between them is equal to the force from the weight, right? this implies that Wg = (V^2A)/[(8PI)D^2], V is voltage, A is the area of the top disc, D is the distance between them: How to explain the equation? what is the significance of 8pi?
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