Three Phase Troubleshooting: Calculating Voltage & Current

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In a balanced delta-connected load of 30+18.86j ohms with a voltage of 400V, the phase voltage is equal to the line voltage. The impedance calculation yields a magnitude of 35.43 ohms at an angle of 32.14 degrees. The current is calculated as I = V/Z, resulting in 11.29 at -32.14 degrees. However, the angle appears to be 30 degrees out, possibly due to a misunderstanding of the phase relationship between line and phase voltages. Clarifying the distinction between line current and phase current is essential for accurate calculations.
robcowlam
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Hi guys,
Im having some trouble with a question about 3 phase power system. I have a balanced delta connected load of 30+18.86j ohms. The voltage is given as 400v @Hz and I am asked to calculate the phase voltage and current using the voltage Vr as the reference.

Now from my knowledge of 3 phase I understand that with this type of load the line and phase voltage are the same (400v) with each phase 120deg lagging from the previous.

Z= 30+18.86j = 35.43 @ 32.14degrees
This leads me to do the calculation:
I = V/Z = (400 @ 0 degrees)/35.43 @ 32.14degrees = 11.29 @ -32.14 degrees.
Repeating this for the other 2 phases gives answers with +/- 120degrees

The magnitude is correct however the angle is 30 degrees out and I cannot see why, the only thing I can think of is that the line voltage is 30degrees out of phase with the phase voltage which I am using as the reference.

Does anyone have any idea if this might be a correct assumption?

Thanks in advance,
Rob
 
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There is a difference in line current and phase current. What is your target variable?
 

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