Throwing a rock - simple mechanics problem

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The problem involves calculating the maximum height and range of a rock thrown at a 30-degree angle with an initial velocity of 12 m/s. The maximum height (h) is calculated using the formula h_max = (v_0^2 * sin^2(α)) / (2g), resulting in a height of 2 meters. The range (Z) is determined using Z = (v_0^2 * sin(2α)) / g, yielding a range of 12 meters. The calculations appear correct, and the use of the equations is confirmed. Overall, the solution is validated as appropriate for the problem.
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Homework Statement



A rock was thrown at the angle of 30 degrees against the horizontal surface, being given a velocity V_0=12m/s. Find the largest height h and the Z - the range of the throw.

Homework Equations



h_{max}=\frac{v_0^2\cdot\sin^2\alpha}{2g}
Z=\frac{v_0^2\cdot\sin 2\alpha}{g}

The Attempt at a Solution



h_{max}=\frac{v_0^2\cdot\sin^2\alpha}{2g}=\frac{144*0,25}{2g}=2m
Z=\frac{v_0^2\cdot\sin 2\alpha}{g}=\frac{144\sqrt{3}/2}{9,81}=12m

Is that OK?
 
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Looks fine to me, if you can use those equations directly.
 
I suppose I will be allowed to :) Thank you.
 
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