Calculating Thrust from Rocket Engine Ejection Velocity

AI Thread Summary
The discussion centers on calculating thrust from a rocket engine's ejection velocity, specifically using an ejection speed of 17,000 ft/sec and a mass flow rate of one pound per second. The initial calculation proposed was F = M/32.2 * Ejection Velocity, resulting in 527 lbs of thrust. However, it was pointed out that thrust should be calculated using the formula Thrust = dm/dt * Vel, emphasizing that thrust is independent of gravity. Clarification was needed regarding the interpretation of "weight of gas ejected," as it could refer to either force or mass flow rate. The consensus is that the thrust calculation is valid when correctly interpreting the units involved.
recon223
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The burned gases of a rocket engine are ejected from the rocket nozzle at a speed of 17,000 ft/sec. If the weight of gas ejected is one pound per second, find the thrust developed by the rocket.


I don't really have an equation to use here but my guess is F = M\32.2 * Ejection Velocity


F in lbs. = [ 1 lb / 32.2] * 17,000 = 527 lbs of thrust


Anyone care to verify that this is correctly calculated or have any ideas on a different calcualtion?
 
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Analysis of units does not support your approach. Also 32.2 ft/s2 is the terrestrial acceleration due to gravity. The rocket could be anywhere-- interstellar space or the moon. Thrust is a function of the rocket, not gravity.
 
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Thrust=dm/dt*Vel

Your work looks correct to me. 1 lbf=32.4 Lbm*ft/Sec2
The units of thrust is lbf
 
This part got me-- "the weight of gas ejected is one pound per second". I read this as a dm/dt of 1lbf/s. If this is read as 1lbm/s then things to fall into place.
 
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