(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A plane of mass 1220 kg has an engine failure when flying with an airspeed of 138 km/h at an altitude of 2960 m on a calm day. It then glides at a constant glide angle (which is the direction of flight below the horizontal) 6.80 degrees towards a safe landing at this constant speed of 138 km/h experiencing a drag force of 1330 N that opposes the direction in which the plane is moving.

(b) Suppose the pilot instead had managed to get the airplane engine started such that he was able to apply full throttle and the airplane climbed along a straight line angled above the horizontal so that it gained altitude at a steady rate of 4.07 m/s. Assuming he was again flying with an airspeed of 138 km/h determine:

i)The thrust force of the engine (that acts in the direction the plane is moving)

2. Relevant equations

g = 9.81 m s-2

F = ma

sin theta = Opp/Hyp

3. The attempt at a solution

The flight angle above the horizontal the plane is flying is 6.09 degrees

.

...|\

...|..\

.1|....\ 2

...|.....\

...+----+

3

1 =2 =Code (Text):F_gravity3 = horizontalCode (Text):F_thrust

Using: sin theta = Opp/Hyp

Hyp = Opp/sin theta

= (1220*9.81)/sin(6.09)

= 112811.2053 N

Actual answer is 2600N

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# Thrust force of an engine

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