How Do You Calculate Velocity Change with Time-Dependent Acceleration?

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To calculate the velocity of the bus at time t2 = 2.10s with a time-dependent acceleration a(t) = 1.24 m/s³, integration of the acceleration function is necessary. The initial velocity at t1 = 1.15s is given as 4.94 m/s. By integrating the acceleration function with respect to time and applying the initial conditions, the constant of integration can be determined. After finding the integrated velocity function, substituting t2 will yield the bus's velocity at that time. This method effectively addresses the challenge of non-constant acceleration in the problem.
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Homework Statement



The acceleration of a bus is given by , a(t) = xa where x = 1.24 m/s3 is a constant. If the bus's velocity at time t1 = 1.15s is 4.94 m/s, what is its velocity at time t2 = 2.10s ?

Homework Equations



I know I have to integrate somehow, but the only equation I can think of to apply is
v(t) = v (initial) + integral of [a dt] with boundaries t and 0.

The Attempt at a Solution



I tried using the basic equations of motion, but they all assume that acceleration is constant... then I tried the above equation but I'm having trouble finding the intial velocity. Please help!
 
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The value of x = 1.24m/s^3 Therefore 'a' must be time t. Integrate the function wrt. time. Using t1 and the velocity find the constant of integration. Now put t2 = 2.1s and find the velocity.
 
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