Time Difference between two inertial frames of reference

AI Thread Summary
In the discussion, two inertial frames of reference, S and S', are analyzed, with S' moving at 0.6c relative to S. The event occurs at S when t = 2 × 10^-7s and x = 50m, prompting a calculation of the corresponding time t' in S'. The initial approach using t = ϒ t' yields an incorrect t' of 1.6 × 10^-7s, while the correct answer is 1.25 × 10^-7s. The discrepancy arises from not accounting for the position of the event in S when applying the Lorentz Transformation. Understanding this transformation is crucial for accurately determining time differences between inertial frames.
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Homework Statement


Let S and S' be two inertial frames of reference where S' is moving at a velocity of 0.6c relative to S.

When x = x' = 0, t = t' = 0, where t and t' are time of the clocks on S and S' respectively and x and x' are the x-coordinates of the S and S' frames respectively.

An event occurs at S when t = 2 × 10-7s and x = 50m. What is t' when the event occurs at S'?

Homework Equations


t = ϒ t'

The Attempt at a Solution


Let t' be the proper time.
t = ϒ t' where t = 2 × 10-7s and v = 0.6c.
Solving, I got t' = 1.6 × 10-7s but the answer is 1.25 × 10-7s.
What am I doing wrong?
 
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You've taken the wrong approach. The time an event takes place in S' depends on both the time and position it takes place in S.

Have you heard of the Lorentz Transformation?
 
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