Time Dilation: A Philosophical Debate or Scientific Reality?

[JesseM]

I think it would be better we leave the v=c case alone. That doesn't lead anywhere. Just introduces divisions by zero and thous singularities in the transformations.

I agree, let's stick with v=0.999c as in your example. Any further thoughts on my last post to you (post #20)?

 

[MeJennifer]

That's not exactly true, since in an accelerated coordinate system the speed of light need not be constant.

Coordinate systems are not physical either. Saying that something is not constant in some coordinate system does not by itself mean anything.

During acceleration, e.g. a != 0 the speed of light is not constant! Hence in conformance with what I stated. Light speed changes during the acceleration of a mass object.

 

[JesseM]

Coordinate systems are not physical either.

You didn't address my point that they can be defined in terms of physical measurements on rulers and clocks. Anyway, even if you don't call them physical, the one-way "speed of light" cannot be defined outside of coordinate systems. Did you mean "all movement between objects of mass and light is absolute, including acceleration" to be a physical statement? If so, what physical measurements were you basing this on?

Light speed changes during the acceleration of a mass object.

Is that supposed to be a physical statement? Again, based on what physical measurements? Certainly if one object is accelerating and is being observed by a second inertial observer, the acceleration of the first doesn't cause any measured change in the speed of light.

 

[Darryl]

here is my NON technical take on this.

http://www.fourmilab.ch/documents/ohmygodpart.html

this is an article on the "oh my god particle" that was detected. it was traveling at

v = 0.9999999999999999999999951 c

Distance[3] Perceived
Object (light years) Travel Time
=============== ================== ===========
Alpha Centauri 4.36 0.43 milliseconds
Galactic nucleus 32,000 3.2 seconds
Andromeda galaxy 2,180,000 3.5 minutes
Virgo cluster 42,000,000 1.15 hours
Quasar 3C273 2,500,000,000 3 days
Edge of universe 17,000,000,000 19 days

 

[RandallB]

RB: " From the traveler view the Planet and Earth cannot be "on the same time"! They cannot "be simultaneous".

And yes you can use v=c if your careful, but if you must use 0.9999999 "

I don't know! Isn't it rather true, that at v=c the length of the whole universe appears contracted to 0. Locks like a singularity to me! So either you allow v=c which means that you accept, that the ship is everywhere at once (earth and alpha centauri) or you declare that v=c is not permissible.

In the first case the Earth and alpha centauri are stationary at the ships position and so is the rest of the whole universe. Nothing moves at v=c!

I didn’t say anything did have a v = c; I said you can do this by using that.
You should have noted that “instantaneous” speed changes work best when looking the movement of the traveler as accounting for the accelerations is not important to understand the issues involved in SR, at least the part you are looking at. This of course means INFINITE acceleration and that not possible, But I notice you seem to be able to do that, because this is a thought experiment and you can assume the Time Change experienced be traveler for such an acceleration to be “0”.

The biggest mistake people make in working SR is transferring an assumption in one frame and transferring that same assumption to the other frame as you have done here by not being careful as I said you needed to be. You claim the ship “is everywhere at once”, I will accept that as so but ONLY in that one frame and no other. I will even accept that the traveler at that instant can see and read the clocks “everywhere” (everywhere also defined as only the line it travels on no matter how long in other frames). But I suspect you are still assuming that as it simultaneously reads the clocks on both Earth and the planet you are still thinking those two reading will be the same just because the ship is everywhere at t = 0; and that I do not accept! Time remains at t = 0 only for the ship and it will see that although Earth and Planet have “synchronized” clocks they cannot read the same time “simultaneously” for the traveler. This is the point not obscure pointless singularity issues that don’t mean anything to this SR problem.

The point of your post is you “don’t understand time dilation” and as JesseM agrees with me: “ …to really "get" all aspects of time dilation you must understand simultaneity, ..” So take the time to work it through CAREFULLY and completely; and I still predict: you will not understand time dilation until you “get” simultaneity. Good Luck, I’ll let you work on it for a few days. If you prefer to use a different approach, that’s OK.

 

[Darryl]

sorry don't mean to mulit post,

that chart is the perceived travel time of the particle traveling at almost c.

so if you were observing Andromeda galazy 2.18 million light years away.

you then jump in your ALMOST c spaceship and start your stop watch, in 3.5 minutes you will arrive at your destination, by YOUR watch. the trip took 3.5 minutes.

but you are now 2 million LY's away from earth, so Earth will be 2million years older.

so in the 3.5 minutes you have lived for, the Earth you just left will have aged 2 million years. if you shine your headlighs at Earth and they see you, it will be 2 million and 3.5 minutes later. than the time frame you left the Earth in. (i really hope I am about right ).
i would not like to guess what you could see, when you travel at those speeds.

I also think, that if you go faster, and reach c. you can't TRALLEL at all !.
as t=0, (probably too simplistic). but if your time stops when you reach c, then as light does not experience TIME at all, if it does not experience time, and cannot travel and distance in 0 time.

so you can't TRAVEL at the speed of light.

or,
at the speed of light, you can't travel.

so if your at the speed of light, by definition you cannot travel, you would start your trip, and instantly end it. no time would pass, making it impossible to measure your own speed, or location ! ?

if your going ALMOST c, and you travel 2million LY's in 3.5 minutes. your going to have to time your trip VERY accuractly, or you will overshoot or undershoot by ALOT.
i guess infinate at c.

 

[eiapeteides]

Time remains at t = 0 only for the ship and it will see that although Earth and Planet have “synchronized” clocks they cannot read the same time “simultaneously” for the traveler. This is the point not obscure pointless singularity issues that don’t mean anything to this SR problem.

I rather stick with v=0.999c. Because the whole hubbub with v=c and t=0 does obscure the issue.

 

[eiapeteides]

JesseM:
I agree, let's stick with v=0.999c as in your example. Any further thoughts on my last post to you (post #20)?

Well, i did draw the events which occur during that little "Thought experiment" in an x-t diagram.

And your explanation does indeed make sense. The Doppler-shift and the difference between real and observed time and distance is quite evident from those diagrams.

Now what I still don't get is the transformation from the Ships to the terrestrial observers view by means of the Lorentz equations. But I'm working on it!

Thanks!

 

[eiapeteides]

so in the 3.5 minutes you have lived for, the Earth you just left will have aged 2 million years. if you shine your headlighs at Earth and they see you, it will be 2 million and 3.5 minutes later. than the time frame you left the Earth in. (i really hope I am about right ).

Isn't it rather 4 mil years after they've seen you depart?

 

[eiapeteides]

here is my NON technical take on this.

http://www.fourmilab.ch/documents/ohmygodpart.html

this is an article on the "oh my god particle" that was detected. it was traveling at

v = 0.9999999999999999999999951 c

Distance[3] Perceived
Object (light years) Travel Time
=============== ================== ===========
Alpha Centauri 4.36 0.43 milliseconds
Galactic nucleus 32,000 3.2 seconds
Andromeda galaxy 2,180,000 3.5 minutes
Virgo cluster 42,000,000 1.15 hours
Quasar 3C273 2,500,000,000 3 days
Edge of universe 17,000,000,000 19 days

OK the traveling times make sense mathematically. But here's the catch:
Is the universe really contracted to a diameter of 17 light-days?
Or is the clock of the traveller slowed so that he only measures 19 days?

Obviously if the traveller stays focused on Earth while he approaches it from the "edge of the universe" he will still count 17,000,000,000 vernal equinoxes.

In other words: Does the motion of the traveller affect the time-perception of the traveller or does it affect the dynamics of the whole universe?

Are those two statements symmetric? That's what the principle of relative motion states if I understand it correctly.

 

[MeJennifer]

Did you mean "all movement between objects of mass and light is absolute, including acceleration" to be a physical statement?

In fact it is the core of Einstein's relativity theory!
For an unaccelerated object light aways escapes at a speed of c while during the acceleration of an object this is no longer the case. Again feel free to give a situation that is in contradiction with this.

Certainly if one object is accelerating and is being observed by a second inertial observer, the acceleration of the first doesn't cause any measured change in the speed of light.

Here you are using movement between objects of mass not objects and light. And as I wrote before movements between objects of mass are relative including acceleration.

 

[MeJennifer]

In other words: Does the motion of the traveller affect the time-perception of the traveller or does it affect the dynamics of the whole universe?

Neither.

Time perception obviously does not change since the laws of physics do not change when something is in relative motion. The dynamics of the universe obviously not change either just because someone is in relative movement. The observed length-contraction is simply an effect of relative motion.

 

[eiapeteides]

Time perception obviously does not change since the laws of physics do not change when something is in relative motion and the dynamics of the universe do obviously not change just because someone is in relative movement. The observed length-contraction is simply an effect
of relative motion

Let's look at Length contraction for a moment. A observer moving at 0.999999999... c sees the universe contracted to a radius of 19 light-days.

He sees the radius of the earth-orbit squeezed to nano meters. And yet those changes have no effect on the orbital motion of the Earth or the moon or mars? We agreed after all that the traveller observes the same orbital events as the Earth bound observer does. How is this possible?

The terrestrial observer does not observe any change in the Doppler-shift of the Microwave background radiation. The traveller on the other hand does, or doesn't he?

Is time dilation the effect of relative motion on space, or is it the effect of absolute motion (against the mw-background) on the visual perception of the traveller?

That's what I can't sort out.

 

[MeJennifer]

Let's look at Length contraction for a moment. A observer moving at 0.999999999... c sees the universe contracted to a radius of 19 light-days.

He sees the radius of the earth-orbit squeezed to nano meters. And yet those changes have no effect on the orbital motion of the Earth or the moon or mars? We agreed after all that the traveller observes the same orbital events as the Earth bound observer does. How is this possible?

Because length contraction is an effect of the traveler's relative motion. Just an effect!

 

[eiapeteides]

Because length contraction is an effect of the traveler's relative motion. Just an effect!

You said that already. My question is: an effect on what?

a)the visual perception of the traveller

or

b)the geometry of the universe that surrounds him?

 

[MeJennifer]

You said that already. My question is: an effect on what?

An effect on how he measures distances of objects in relative motion.

 

[eiapeteides]

An effect on how he measures distances of objects in relative motion.

So it is a sensory effect! It affects the sensors and scales and thereby the process by which the traveler measures lengths and time intervals?

I was, and still am, under the impression that relativity means that motion has an effect on "Space-Time" itself and not just on the way we measure it.

Am I wrong?

 

[MeJennifer]

So it is a sensory effect! It affects the sensors and scales and thereby the process by which the traveler measures lengths and time intervals?

It does not affect the sensors and the scales, since the sensors and the scales are not in relative motion to the one who measures the results.

It is simply the case that if two objects of mass are in relative motion with each other that from each perspective the other object's time dilates, its mass increases and that the distance between them decreases. Why? Well because of the fact that light always escapes or approaches an object of mass at the same speed regardless or the relative motion between another object of mass.

I was, and still am, under the impression that relativity means that motion has an effect on "Space-Time" itself and not just on the way we measure it.

Motion does not effect space-time, that would be impossible since there is no motion in space-time.

 

[eiapeteides]

Motion does not effect space-time, that would be impossible since there is no motion in space-time.

So who should one interpret the content of a previous post:

http://www.fourmilab.ch/documents/ohmygodpart.html

this is an article on the "oh my god particle" that was detected. it was traveling at

v = 0.9999999999999999999999951 c

Distance[3] Perceived
Object (light years) Travel Time
=============== ================== ===========
Alpha Centauri 4.36 0.43 milliseconds
Galactic nucleus 32,000 3.2 seconds
Andromeda galaxy 2,180,000 3.5 minutes
Virgo cluster 42,000,000 1.15 hours
Quasar 3C273 2,500,000,000 3 days
Edge of universe 17,000,000,000 19 days

Does that not mean that the Galaxies and the distances between them appear contracted to an observer co-moving with the particle?

Looks like space-time contraction to me.

 

[MeJennifer]

Looks like space-time contraction to me.

There is no such thing as space-time contraction.

In relativity we have:
When two objects (of mass) are in relative motion with each other each object will measure the other object's distance to be shorter, clock to run slower and mass to increase compared to if they would not be in relative motion with each other.

 

[JesseM]

Did you mean "all movement between objects of mass and light is absolute, including acceleration" to be a physical statement?

In fact it is the core of Einstein's relativity theory!

What's at the core of his theory is that light moves at c in every inertial coordinate system, or equivalently that each inertial observer will measure the speed of light to be c if he uses rulers and clocks at rest relative to himself. But your claim that "the traveler always travels at 0c relative to light" doesn't make sense in either of these terms.

Again, please provide some rigorous definition--whether expressed in terms of coordinate systems or in terms of physical measurements--of what you mean in general by the phrase "A is moving at velocity v relative to B", in such a way that if A=the traveler and B=the light beam, v would equal 0 rather than c. If you can't do this, then your statement cannot possibly make any sense as physics.

For an unaccelerated object light aways escapes at a speed of c while during the acceleration of an object this is no longer the case. Again feel free to give a situation that is in contradiction with this.

It's not that I think your statement is clearly wrong, it's just that I have no idea what you even mean. I would certainly agree that in the coordinate system of an unaccelerated object light always escapes at a speed of c, and that in the coordinate system of an accelerating object this would not necessarily be the case, but you claim not to be talking about coordinate systems. So what are you talking about? Surely it's meaningless to ask "how fast is the light escaping" without having in mind either a coordinate system or a physical procedure for measuring speed?

 

[MeJennifer]

Perhaps you are confused by the term acceleration.
In Newtonian thinking a comet falling towards the Earth due to the Earth's gravity is accelerating but in relativity the rock is not accelerating at all.
When I talk about acceleration it is not some coordinate specific thing but a physical thing. An unaccelerated object is on a geodesic in space-time while an accelerated object is not. Acceleration is a measurable physical quantity.

Show me a case where an object of mass that is not accelerating is either emitting or absorbing light at a speed different from c, or a case where an object that is accelerating (as in relativity not in some coordinate specific sense) is emitting or absorbing light at the speed of c.

I wager that you will not find a case like that.

So the speed differential between such an object of mass and emitted or absorbed light is always c unless the mass object accelerates. From this we can conclude that the mass object must be at rest compared to light and thus the speed of a mass object relative to light is always 0c unless it accelerates. Also if light would be emitted in all directions forming a sphere the unacellerated mass object would aways be exactly in the middle and the sphere's radius would grow by c. The relative motion of this mass object, so the motion compared with other mass objects, would be completely irrelevant to this phenomenon.

 

[JesseM]

Perhaps you are confused by the term acceleration.
In Newtonian thinking a comet falling towards the Earth due to the Earth's gravity is accelerating but in relativity the rock is not accelerating at all.
When I talk about acceleration it is not some coordinate specific thing but a physical thing. An unaccelerated object is on a geodesic in space-time while an accelerated object is not. Acceleration is a measurable physical quantity.

Of course acceleration is a measurable physical quantity, but you measure it using rulers and clocks. You are still not answering any of my questions about what measurements you are thinking of when you say things like "the traveler always travels at 0c relative to light" and "For an unaccelerated object light aways escapes at a speed of c while during the acceleration of an object this is no longer the case." The first quote does not obviously have anything to do with acceleration, and the second quote would seem to imply you're talking about how an accelerated vs. unaccelerated observer would measure the speed of light, not how to measure whether the observer himself is accelerating, which I agree is unambiguous.

Show me a case where an object of mass that is not accelerating is either emitting or absorbing light at a speed different from c or a case where an object that is accelerating (as in relativity not in some coordinate specific sense) is emitting or absorbing light at the speed of c.

Who is supposed to be measuring the speed of light, and using what method? If you have an accelerating object emitting light, but the speed of light is being measured by an unaccelerating observer's rulers and clocks, than the light will be measured to be traveling at c. The speed of light has everything to do with what coordinate system you are using, or what set of rulers and clocks are being used to perform the measurement, and nothing to do with whether the object emitting the light is accelerating or not.

So the speed differential between such an object of mass and emitted or absorbed light is always c unless the mass object accelerates. From this we can conclude that the mass object must be at rest compared to light and thus the speed of a mass object relative to light is always 0c unless it accelerates.

You still have provided absolutely no justification for why the second sentence makes sense. In all of physics, "the speed of A relative to B" means either the speed that A measures B to be moving (or vice versa), or perhaps the speed that some third observer sees the distance between A and B changing (the 'closing speed'). But in both of these cases, to say the relative speed is 0c would mean that the distance between A and B is remaining unchanged, so they are measured to be at rest with respect to each other, but that clearly isn't the case with the light beam. So, either you have invented some totally new definition of what it means to say "A is moving at speed v relative to B", or else you have no well thought-out basis for this statement. If you have in fact invented a new definition, it should be simple for you to answer this question I posted earlier:

please provide some rigorous definition--whether expressed in terms of coordinate systems or in terms of physical measurements--of what you mean in general by the phrase "A is moving at velocity v relative to B", in such a way that if A=the traveler and B=the light beam, v would equal 0 rather than c.

Also if light would be emitted in all directions forming a sphere the unacellerated mass object would aways be exactly in the middle and the sphere's radius would grow by c.

As measured by rulers and clocks (or coordinate system) which are at rest relative to the unaccelerated object. On the other hand, if you measure things using rulers and clocks which are moving at constant velocity relative to the unaccelerated object, you will still measure an expanding sphere of light, but the center will be the mark on your ruler where the light was originally emitted, while the object itself will be moving away from this mark and will be closer to one part of the sphere than the other.

In any case, I still have no idea how you think the expanding light-sphere sheds any light on your statement that the emitter is moving at 0c relative to the light. Once again, please provide some general definition of what you mean by "A is traveling at speed v relative to B", such that if we plug in A=the emitter and B=the light, we conclude that v=0 rather than v=c, as would be concluded by most ordinary definitions of "relative speed".

 

[MeJennifer]

If you have an accelerating object emitting light, but the speed of light is being measured by an unaccelerating observer's rulers and clocks, than the light will be measured to be traveling at c.

In your case you would be measuring the absorbing speed of light by an unaccelerated observer. What makes you think that the fact that light was emitted by an accelerated object has anything to do wth the results of the measurement?
It does not in relativity.

Again light is always emitted and absorbed at the speed of c unless the observer is accelerating. Frankly this is a rather obvious statement, I really do not see what your problem is with it.

 

[JesseM]

In your case you would be measuring the absorbing speed of light by an unaccelerated observer. What makes you think that the fact that light was emitted by an accelerated object has anything to do wth the results of the measurement?

Of course I don't think this, but I was asking the question to try to make sense of what you were arguing, which is still completely unclear to me.

Again light is always emitted and absorbed at the speed of c unless the observer is accelerating. Frankly this is a rather obvious statement, I really do not see what your problem is with it.

The statement's meaning is obvious if you are talking about the speed of light in an accelerated observer's coordinate system, but I have no idea what it could mean independently of a statement about coordinate systems. Again, do you have any specific notion of how this accelerating observer is measuring the speed of light? If not, how does it make sense to talk about the "speed" of anything outside of either a coordinate system or a well-defined measurement procedure?

Also, you still have not addressed my other question about what you mean when you talk about a relative speed of 0c rather than 1c between an inertial observer and a light beam:

please provide some rigorous definition--whether expressed in terms of coordinate systems or in terms of physical measurements--of what you mean in general by the phrase "A is moving at velocity v relative to B", in such a way that if A=the traveler and B=the light beam, v would equal 0 rather than c.

 

[MeJennifer]

Also, you still have not addressed my other question about what you mean when you talk about a relative speed of 0c rather than 1c between an inertial observer and a light beam:

Again it is obvious, how could you posibly reason that the relative speed of the mass object is c?
A non accelerating mass object emitting light in all directions will create a growing sphere growing with the speed of c and with the mass object always in the middle. How could you possibly argue that the mass object is going with any speed except 0 relative to the speed that the light is escaping from it?
Furthermore the relative speed of the mass object in question compared to other mass objects is completely irrelevant to this.

 

[JesseM]

Again it is obvious, how could you posibly reason that the relative speed of the mass object is c?

Er, because the only definition of "relative speed" in physics is the rate that the distance grows between two things, and the distance between the object and the light is growing at a rate of 1 light year per year. According to every definition I know of, to say the "relative speed" between the two is 0c means they are maintaining a constant distance.

A non accelerating mass object emitting light in all directions will create a growing sphere growing with the speed of c and with the mass object always in the middle. How could you possibly argue that the mass object is going with any speed except 0 relative to the speed that the light is escaping from it?

Obviously in the object's own rest frame, its speed is 0 (and the object only stays at the center of the expanding light-sphere in this frame, in other inertial frames it will move closer to one side of the sphere than the other). But according to all standard definitions this is not the speed of the object relative to the light, it is the speed of the object relative to its own frame.

If we're living in a Newtonian universe, and I'm driving at 30 mph down the road, and one car is going at 10 mph in the opposite direction while another is going at 70 mph in the same direction, then if all three cars start from a single location, my car will always remain at the center of the expanding line segment whose edges are defined by the positions of the two other cars--would you say that this somehow means my speed is 0 relative to these cars, in spite of the fact that each one is moving away from me at 40 mph?

Once again, if you don't have some general definition of what you mean by "relative speed", which can cover cases that don't involve light like the case of cars moving relative to one another at sublight speeds, then you're simply talking gibberish.

 

[MeJennifer]

Obviously in the object's own rest frame, its speed is 0 (and the object only stays at the center of the expanding light-sphere in this frame, in other inertial frames it will move closer to one side of the sphere than the other).

I suppose you mean that for all other observers who are in relative motion to the object in question the object does not stay in the center right? Well that is true, and that is where the Lorentz transformations come in. The other observers see it like that because they are in relative motion with the object in question.

If we're living in a Newtonian universe, and I'm driving at 30 mph down the road, and one car is going at 10 mph in the opposite direction while another is going at 70 mph in the same direction, then if all three cars start from a single location, my car will always remain at the center of the expanding line segment whose edges are defined by the positions of the two other cars--would you say that this somehow means my speed is 0 relative to these cars, in spite of the fact that each one is moving away from me at 40 mph?

Right, but the point is that we are not living in a Newtonian universe! For light things are rather different as Einstein discovered about a century ago! He discovered that when we are in an inertial state we cannot "catch up" with light, that our speed differential is always c.
It is interesting because your example is exactly what puzzled Einstein. "Why doesn't it work for light this way" is what he thought. And now it seems to puzzle you.
One of the basics in relativity is the fact that light is always emitted from and absorbed by an unaccelerated mass object at a fixed speed, and this speed is c. It does not matter if something is moving at x relative to another object of mass, it could move at 99.99999% relative to my big toe, it is totally irrelevant. You can make up 100 of your frames that are in relative motion but it would not matter in the least.
For light the object is always standing still unless it is accelerating.

 

[JesseM]

Right, but the point is that we are not living in a Newtonian universe! for light things are rather different as Einstein discovered about a century ago!

I only had it be a Newtonian universe to make the math a little easier, but you could also pick an example of objects moving at sublight speeds in SR. For example, suppose in your frame I am moving at 0.6c, and there is another ship moving at 0.385c in the opposite direction, while a second ship is moving at 0.946c in the same direction. In this case, in my own rest frame, both ships would be moving at 0.8c in opposite directions from me, so I would remain at the center of the expanding line segment with the edges defined by the positions of the ships. Would you therefore say that somehow my speed relative to the ships is 0c rather than, say, 0.8c (the speed of each ship in my rest frame), or 1.185c and 0.346c (the speed with which the distance between my ship and each of the other ships is growing in your own frame)?

One of the basics in relativity is the fact that light is always emitted from and absorbed by an unaccelerated mass object at a fixed speed, and this speed is c. It does not matter if something is moving at x relative to another object of mass, it could move at 99.99999% relative to my big toe, it it is totally irrelevant.

Yes, I certainly agree with this, at least if we are looking at things from an inertial reference frame.

For light the object is always standing still unless it is accelerating.

This statement has no obvious connection to the previous one, it seems like a non sequitur. What does it mean to talk about what things look like "for light"? Light has no rest frame in relativity, as I'm sure you know. And even if we consider something like how another ship moving at v relative to me will see me in the limit as v approaches c, for the other ship my own velocity would approach c in this limit, not 0.

 

[MeJennifer]

I only had it be a Newtonian universe to make the math a little easier, but you could also pick an example of objects moving at sublight speeds in SR. For example, suppose in your frame I am moving at 0.6c, and there is another ship moving at 0.385c in the opposite direction, while a second ship is moving at 0.946c in the same direction. In this case, in my own rest frame, both ships would be moving at 0.8c in opposite directions from me, so I would remain at the center of the expanding line segment with the edges defined by the positions of the ships. Would you therefore say that somehow my speed relative to the ships is 0c rather than 0.8c?

No of course not, we are not talking about light here but about relative motion of mass objects, something entirely different.
With light it is different.

You say it has something to do with frames, but a frame is simply a concept. There is nothing physical about frames, and in GR they are next to completely useless. All we have is objects of mass that are or are not in relative motion with other obects of mass, inertial v.s. accelerated state and the speed of light, and the fact that light always is emitted and always escapes at c and that that is independent of relative motion.
These are the building blocks of relativity not frames!

I do not see one bit of a problem with the statement that for light all mass objects either stand still or accelerate even if that means you cannot construct one of your frames on it.