Time of Bomb Dropped from 2000m: Calculation

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To calculate the time a bomb is in the air when dropped from a height of 2000 m by a plane flying at 720 km/h, the vertical motion is independent of the horizontal speed. The appropriate formula to use is delta y = Vi delta t + 1/2 a delta t^2, focusing solely on vertical motion where the initial vertical velocity is zero. Using the acceleration due to gravity (g = 9.8 m/s²), the time of free fall can be calculated. The correct calculation shows that the bomb takes approximately 2.7 seconds to reach the ground. Thus, the time the bomb was in the air is determined solely by its vertical descent.
hype_chicky
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if a plane is flying at 720 km/h and drops a bomb when it is 2000 m high what is the length of time the bomb was in the air?

So Viinitial is 720 km/h and d is 2000 m , g is 9.8 and to solve for t would i use the formuladeltay = Videltat + 1/2adeltay t^2?
 
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the vertical and horizontal component are independent, the result is not related to how fast the plane travel horizontally
 
delta x = viX dellta t
2000 = 720 km/h (delta t)
delta t = 2000m/ 720 km/h. Therefore the length of time the bomb was in the air is 2.7 seconds?
 
hype_chicky said:
So Viinitial is 720 km/h and d is 2000 m , g is 9.8 and to solve for t would i use the formuladeltay = Videltat + 1/2adeltay t^2?
This is the correct equation to use, but not the correct initial velocity. All you care about is the vertical motion (which, as vincentchan points out, has nothing to do with the horizontal speed of the plane), so what's the initial speed in the vertical direction?
 

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