Time on watch dependent on air temperature?

AI Thread Summary
The discussion revolves around calculating the time delay for a watch set by a factory whistle 3 miles away, considering the speed of sound at 20 degrees Celsius. The speed of sound is noted to be approximately 1130 feet per second, leading to a calculated time of about 14.018 seconds for sound to travel that distance. Participants emphasize the relationship between distance, speed, and time, confirming the formula T = V/D as the correct approach. There is some confusion regarding the calculations, with one participant questioning an alternative result of 46 seconds, which seems implausible. Ultimately, the consensus supports the 14.018 seconds as a reasonable estimate for the delay.
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Homework Statement


Can anyone give me a hand on how to start this? I would attempt a solution but I've tried over and over and can't seem to get anywhere.

A man sets his watch at noon by the sound of a factory whistle 3 miles away. If the temperature of the air is 20-degrees C, how many seconds slow will his watch be by the time at the factory?


Homework Equations





The Attempt at a Solution

 
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How fast does sound travel through air at 20C?
 
DaveC426913 said:
How fast does sound travel through air at 20C?


Still a little lost here:

In general, at 68 F (20 C) sound travels at 1130 ft/sec (344.4 m/sec.)
3 miles = 15 840 feet
3 miles = 4 828.032 meters

but not sure how to put it together in equation format?
 
kriegera said:
Still a little lost here:

In general, at 68 F (20 C) sound travels at 1130 ft/sec (344.4 m/sec.)
3 miles = 15 840 feet
3 miles = 4 828.032 meters

but not sure how to put it together in equation format?

Really?

You've got a velocity and a distance; you're being asked to solve for time.

You say you're tried over and over. Show your attempts.
 
DaveC426913 said:
Really?

You've got a velocity and a distance; you're being asked to solve for time.

You say you're tried over and over. Show your attempts.

T=V/D =
T=15840 ft/ 1130ft/s = 14.018 seconds.
 
kriegera said:
T=V/D =
T=15840 ft/ 1130ft/s = 14.018 seconds.

Does that sound about right? What does your intuition tell you? Think of thunder & lightning.
 
DaveC426913 said:
Does that sound about right? What does your intuition tell you? Think of thunder & lightning.

I did find something that used c = d / Δ t - where c was speed of sound so
Δ t = d / c = 15,840/344.4 = 46 seconds but that seems too long a delay for three miles no?

As far as thunder and lightning, lightning strikes first b/c it travels faster in air than sound. The speed of a sound wave in air depends upon the properties of the air, namely the temperature and the pressure so it makes sense for
Time=distance/speed =
Time=15,840 ft/1130 ft/sec.
14.018 sec

but I'm still second-guessing it.
 
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