Time slows at the speed of light

DianaPrince
Messages
1
Reaction score
0
Hi,
I am not exactly sure how to present this question. Even thinking about it creates some confusion,so I will only try my best. My question is about special relativity. Since the first time I saw Carl Sagan's Cosmos series, I have been fascinated by this, but still don't totally get it. I can accept as fact that time slows down as you approach the speed of light, but actually understanding this presents a whole different problem.

If for example time elapses differently for a stationary observer than it does for someone traveling at the speed of light, how can we determine how much time has elapsed? Suppose I am standing with a friend in an open field. My friend takes a round trip ride from Earth to the sun at the speed of light (let's just pretend that he didn't get burnt to a crisp). Once he leaves my side in his imaginary spacecraft , I stand there waiting for him to return, which should only take about 16 minutes (round-trip). What will I notice when he returns? Is the amount of time that he was gone different for him than it was for me? For how long (stationary-earth-time) must he travel at the speed of light in order for there to be a visible difference in the aging process once we meet back up? If we as humans are accustomed to time passing at a very particular rate, what experience does the person traveling at the speed of light have? For example, he goes on a speed-of-light-journey let's say to Proxima Centauri. I sit around waiting for 8 1/2 years for him to get there and back. Does he feel as if he were only on a short journey? If so, according to his clock and his perception of elapsed time, how long did his journey last - for him? I hope I made my question clear. Any answers or additional info to help me understand this would be appreciated.
Jasmin
 
Physics news on Phys.org
Welcome to PF!

Hi Jasmin! Welcome to PF! :smile:
DianaPrince said:
… Once he leaves my side in his imaginary spacecraft , I stand there waiting for him to return, which should only take about 16 minutes (round-trip). What will I notice when he returns?

Nothing … he can't get any younger, and you'll only be 16 minutes older! :smile:
If we as humans are accustomed to time passing at a very particular rate, what experience does the person traveling at the speed of light have? For example, he goes on a speed-of-light-journey let's say to Proxima Centauri. I sit around waiting for 8 1/2 years for him to get there and back. Does he feel as if he were only on a short journey?

If he goes on an almost-speed-of-light-journey, then everything seems normal to him (apart of course from the immense g-forces at the start the turn-round and the finish!), and yes he feels as if he were only on a short journey. :smile:
If so, according to his clock and his perception of elapsed time, how long did his journey last - for him?

Depends how close he was to the speed of light … could even be less than a nano-second …

The precise factor is √(1 - v²/c²), so the closer v is to c, the slower his time is. :smile:
 
I started reading a National Geographic article related to the Big Bang. It starts these statements: Gazing up at the stars at night, it’s easy to imagine that space goes on forever. But cosmologists know that the universe actually has limits. First, their best models indicate that space and time had a beginning, a subatomic point called a singularity. This point of intense heat and density rapidly ballooned outward. My first reaction was that this is a layman's approximation to...
Thread 'Dirac's integral for the energy-momentum of the gravitational field'
See Dirac's brief treatment of the energy-momentum pseudo-tensor in the attached picture. Dirac is presumably integrating eq. (31.2) over the 4D "hypercylinder" defined by ##T_1 \le x^0 \le T_2## and ##\mathbf{|x|} \le R##, where ##R## is sufficiently large to include all the matter-energy fields in the system. Then \begin{align} 0 &= \int_V \left[ ({t_\mu}^\nu + T_\mu^\nu)\sqrt{-g}\, \right]_{,\nu} d^4 x = \int_{\partial V} ({t_\mu}^\nu + T_\mu^\nu)\sqrt{-g} \, dS_\nu \nonumber\\ &= \left(...
In Philippe G. Ciarlet's book 'An introduction to differential geometry', He gives the integrability conditions of the differential equations like this: $$ \partial_{i} F_{lj}=L^p_{ij} F_{lp},\,\,\,F_{ij}(x_0)=F^0_{ij}. $$ The integrability conditions for the existence of a global solution ##F_{lj}## is: $$ R^i_{jkl}\equiv\partial_k L^i_{jl}-\partial_l L^i_{jk}+L^h_{jl} L^i_{hk}-L^h_{jk} L^i_{hl}=0 $$ Then from the equation: $$\nabla_b e_a= \Gamma^c_{ab} e_c$$ Using cartesian basis ## e_I...

Similar threads

Replies
93
Views
5K
Replies
23
Views
3K
Replies
11
Views
2K
Replies
4
Views
1K
Replies
6
Views
1K
Replies
5
Views
357
Back
Top