Time Spent in Top and Bottom 25 cm of Basketball Player's Jump?

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A basketball player jumping 70 cm vertically spends time in both the top and bottom 25 cm of the jump, which can be calculated using the equations of motion under constant acceleration. The acceleration due to gravity is -9.81 m/s², and the velocity at the peak of the jump is 0 m/s. To find the time spent in the top 25 cm, the relevant equations can be applied to determine the time taken to reach that height from the peak. Similarly, the time spent in the bottom 25 cm can be calculated from the initial jump height to the ground. Understanding these calculations is essential for analyzing a player's jump dynamics effectively.
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A basketball player grabbing a rebound jumps 70 cm vertically.
How much (total) time does the player spend in the top 25 cm of this jump?
How much (total) time does the player spend in the bottom 25 cm of this jump?
 
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What are the relevant equations? What is your attempt at solving this?
 
WOW thanks for helping
 
You aren't going to be given an answer without showing that you've tried, and you definitely aren't going to be given an answer for being rude.

Have some hints:
a = -9.81 m/s/s
s (displacement) = 0.70 m
v at peak of jump = 0 m/s

use constant acceleration formulae.
 
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