When, [itex]dE/E >> 1[/itex], isn't it possible to have a time-varying electric field that produces a displacement current greater than the conduction current? Would it also be the case that one could achieve this effect by switching a circuit on for a small period of time, say where [itex]T << 1/f_0[/itex]? What happens if a person were to switch a circuit on quickly, but switch it off much quicker? It would cause a massive back-spike of displacement current in the opposite direction. If there was an inductance, there might also be some resistance to changing it before and after it was established. If the E-field was produced by discharging a capacitor into an inductor, what happens to the back-spike of displacement current, generated by disconnecting the inductor from the capacitor, once it arrives at the capacitor? Does displacement current (provided it has voltage) transfer reactive power or real power? Is there a way to quantify the power conveyed through the displacement current, and if so, what is it equal to? And finally, what energy source does displacement current draw upon to exist in the first place, when created by shorting a capacitor, given that it is not proportional to the movement of free electrons away from the capacitor under various situations satisfying the conditions [itex]dE/E >> 1[/itex] and [itex]T << 1/f_0[/itex]?