Finding f and d in Lab Experiment

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The discussion focuses on determining the focal length (f) and the distance (d) in a lab experiment involving a ray box. The method includes measuring the length of the opening, varying the distance (x) from the tube to the screen, and recording the magnification (m). A graph of m against x is plotted, and the relationship m = (x + d) / f - 1 is used to derive f and d. Participants confirm that the gradient of the graph represents 1/f, while the y-intercept relates to d. The conversation concludes with a participant correcting their earlier mistake regarding the calculation of d.
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Homework Statement



I have to find f and d
Here's the method of the lab
Method: The length of the opening in the ray box was measured and
recorded. The equipment was set up as shown in the diagram.
The distance, x, of the tube from the screen was varied and
recorded. The magnification, m, for each value of x was
determined and recorded; this was obtained by focusing
the image of the cross-wire formed on the screen and
measuring the length of the image using the graph
paper attached to the screen. At least 8 values of x
and m were determined. A graph of m against x
was plot and a best straight line was drawn through
the points. Theory suggested that

m = (x + d) - 1
f
By writing the equation above in the form y=mx + c,
the focal length of the lens and the position of the lens
from end A of the cardboard tube was determined.

153pjj5.jpg

Homework Equations


m = (x + d) - 1
f

The Attempt at a Solution



I plotted a graph of m against x gradient = m/x

so gradient would = 1/f right?

then i could solve for d after?
 
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lionely said:

Homework Statement



The equipment was set up as shown in the diagram.

Hi lionely. Can you post the diagram?
 


it's there now
 


lionely said:

2. Homework Equations

m = (x + d) - 1
f
Just to make sure, is this the equation?

##m = \frac{x+d}{f} -1##

The Attempt at a Solution



I plotted a graph of m against x gradient = m/x

so gradient would = 1/f right?

then i could solve for d after?

Yes, the gradient (slope) would be 1/f. The y-intercept of your graph is related to d. So, you could use the y-intercept to find d.
 


Okay thank you!
 


I get a negative value when i try to work out d... I think something is wrong.
 


Nevermind I made a mistake ...
 
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