How to Find the Balancing Mass and Supporting Tension in a Beam?

AI Thread Summary
To find the balancing mass and supporting tension in a 1m long beam with a 5N weight, the forces and torques acting on the system were analyzed. The equations used included summing forces in the vertical direction and calculating torque about a pivot point. The initial calculations suggested a mass of 6.5kg and a tension of 8.45N, but the user recognized discrepancies in their force values leading to incorrect results. A request for clarification on the errors in the calculations was made, indicating the need for further assistance. Accurate calculations of forces and torques are crucial for determining the correct balancing mass and supporting tension.
Kingrick
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Homework Statement


for the 1m long, 5N beam below, find the balancing mass m and the supporting tension T

T
----- ^
| | | ------
| m | |(25cm) | 2kg |
---------------------------------(1m)


Homework Equations



f=ma

torque= Fxr
cross product, F x rsinx



The Attempt at a Solution



first i summed the forces

Fx=0, no forces acting in x.

Fy=0

forces acting

1. m1g= 9.8m1
2> m2g= 19.6N
3. CG= 5n
4. T =?

9.8m1 + 19.6N + 5N - T= 0

so T = 9.8m1 + 24.6N


next I summed the torques

19.6N * 0.75m + 5 * 0.25 -(9.8)(.25m)m1 = 0

m1 = 6.5kg

Fm1= 63.7N

the actual answer of the force is -88.7N, and the T=8.45

seeing how i have the wrong force values i know that my T will be wrong using it. if anyone can show me where I went wrong in this one that would be very helpful thanks.
 

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