Solve Torque & Equilibrium Homework

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    Equilibrium Torque
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A meter stick weighing 235 g is supported by two strings at the 0 cm and 90 cm marks. The equilibrium equations indicate that the sum of the forces from the strings must equal the weight of the stick. The torque equation also needs to account for the location of the stick's weight, which acts at its center of mass. The discussion emphasizes the importance of correctly converting mass to weight and understanding the stick's center of gravity for accurate calculations. Proper application of torque and equilibrium principles is essential for solving the problem.
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Homework Statement



A meter stick with a mass of 235 g is supported horizontally by two vertical strings, one at the 0 cm mark and the other at the 90 cm mark

Homework Equations



t=r F sin θ

The Attempt at a Solution



F1=the first string at zero
F2=the second string

F1+F2-235=0

(F1x0)+(F2x90)-(235)=0
 
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tyerra123 said:
F1+F2-235=0
Careful: 235 is the mass (in grams), not the weight.

(F1x0)+(F2x90)-(235)=0
Same problem as above plus one more: Where does the weight of the stick act?
 
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