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richard7893
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For Torque of current carrying wire in magnetic field why does the magnetic field of the current carrying wire itself not contribute to torque?
Torque of a current carrying wire in magnetic field
AI Thread Summary
The torque on a current-carrying wire in a magnetic field is not influenced by the wire's own magnetic field because that field does not exert a force on itself. The magnetic field generated by the wire circulates around it and does not interact directly with the wire to produce torque. Consequently, the wire does not experience a force from its own magnetic field. This principle is fundamental in understanding electromagnetic interactions. Overall, the current-carrying wire only responds to external magnetic fields for torque generation.
Kindly see the attached pdf. My attempt to solve it, is in it.
I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction.
I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance)
My thoughts for the first case , one of them must be 12 volt while the other is 0
The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Here is what I tried
This question was actually asked in one of our engineering entrances.
The answer was 1D.
My teachers say that we have to use μₘ/fₘ to get to this answer. I cannot understand why. I'll be really glad if you could tell me the exact definition of power (numerically) that works in all scenarios.
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