Torque on a hinge to a gate that is 69 inches long

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To lift a 69-inch gate that requires 50 lbs of force at a little over a 90-degree angle, the torque needed can be calculated using the formula torque = force x distance. Given the length of the gate, the torque required would be 50 lbs multiplied by 69 inches, which equals 3450 inch-pounds. To offset the majority of the weight, a torsion spring must provide a torque close to this value. A free body diagram would help visualize the forces acting on the gate and the spring's placement. Proper calculations and diagrams are essential for determining the exact specifications needed for the torsion spring.
ewhite17
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I have a gate that is 69 inches long and it takes 50 lbs of force to lift at the end of the gate when it is extended at a little over a 90 degree angle. How many foot pounds of torque in a torsion spring will be needed to lift the gate or at least offset the majority of the weight?
 
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Draw a free body diagram.
 
I built a device designed to brake angular velocity which seems to work based on below, i used a flexible shaft that could bow up and down so i could visually see what was happening for the prototypes. If you spin two wheels in opposite directions each with a magnitude of angular momentum L on a rigid shaft (equal magnitude opposite directions), then rotate the shaft at 90 degrees to the momentum vectors at constant angular velocity omega, then the resulting torques oppose each other...

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