A bar of length L supports a mass, m2 at the end. It is fastened by a pivot at one end to a wall which is at an angle θ to the horizontal. The bar is supported by a cord a distance x from the wall. The mass of the uniform bar is m1. I already solved for the tension: T=(1/2m1 + m2) (L/x) g
What is the horizontal component of the force exerted on the bar by the wall? Let right be the positive direction.
τ= Ʃ(Fdsinθ) τ=0
The Attempt at a Solution
I set the torques equal to each other at the end with the mass, m2 so that I could determine Ncosθ, the vertical component of the normal force exerted by the wall. I also tried using the same torque equations at the midpoint of L and where T is exerted.