Torque Requirement for 25mm dia Shaft 600mm Length w/ Gear

  • Thread starter Thread starter Analysis
  • Start date Start date
  • Tags Tags
    Torque
AI Thread Summary
The discussion centers on determining the torque required for a 25mm diameter, 600mm long shaft with a gear attached, driven by an external load applied via a lever arm. The user seeks clarification on their approach, which involves calculating reaction forces at the bearings and using the friction coefficient to determine the necessary torque. Key concerns include the potential increase in friction when force is applied, the appropriate values for reaction forces at the ends of the shaft, and the relationship between running torque and starting torque for motor selection. Additionally, the user questions the influence of gear radius on the torque required to drive the shaft. Overall, the conversation emphasizes the need for accurate calculations and understanding of friction in torque requirements.
Analysis
Messages
52
Reaction score
0
Dear all,

I need clarification regarding torque requirement in the following arrangement.
Imagine a shaft 25mm diameter 600mm length simply supported and one end
gear is attached to drive the shaft.
Load is externally applied via lever arm and different material(polymer) same
diameter is in contact.
My query is what is the torque required to drive this shaft arrangement.
Load,shaft geometries,speed are the known values.

My approach is assumed that at static condition load is applied over shaft, finding
the reaction force at each bearing end and from this force multiplied by bearing
mean radius with co efficient of friction of bearing which is normally(0.0025max).


Is the approach is correct?

1)My suspect is when applying force to the bearing, friction coefficient will

increase how to change of friction is accommodated?
2)Rollers in contact with pressure to overcome frictional resistance will be less

only i.e. shaft in contact assume that 100 N is acting,to overcome this force we

will multiply with friction coefficient of two materials say 0.3 and the calculation is

100 x 0.30=30N is enough to overcome the force of 100 N
3)To find reaction force at the ends can i use of 30N instead of 100N?

4)Suppose reaction force will changes in each end,say one end is 50 N and
another end is 35N can i take higher value?

5)Above is that running torque what will the empirically starting torque to select
induction motor or servo drive motor specification.can i take say 1.5 times
running torque for both? Can i use T=IxAlpha approach?

6)In this gear is going to drive the shaft gear PCD has any influences?bcoz gear
radius is used to drive the shaft torque?

Thanks in advance
Prakash

(Since image is not uploading i am narrating the problem)
 
Engineering news on Phys.org
Hello, Prakash. You continue to try to get someone else to do your work, don't you? I have to say, I am amazed at your persistence!
 
Dr.D said:
Hello, Prakash. You continue to try to get someone else to do your work, don't you? I have to say, I am amazed at your persistence!



Dearsirs,
Sorry in the case of wrong ,whatever my clarifications /doubts only posting i am not the person getting my work done thro others.Also my posts are narrating the approaches of my work and seeking others comments that's all.This is to enhance my theoretical knowledge.From ur point of view what are the questions can we post?

From the above In the torque requirement querey my suspect is while rotating we can easily overcome the load applied by top roller,comparitevely taking total load used to finding reactions from that am calculating the torque...?

Thanks for ur comment

Prakash
 
Posted June 2024 - 15 years after starting this class. I have learned a whole lot. To get to the short course on making your stock car, late model, hobby stock E-mod handle, look at the index below. Read all posts on Roll Center, Jacking effect and Why does car drive straight to the wall when I gas it? Also read You really have two race cars. This will cover 90% of problems you have. Simply put, the car pushes going in and is loose coming out. You do not have enuff downforce on the right...
I'm trying to decide what size and type of galvanized steel I need for 2 cantilever extensions. The cantilever is 5 ft. The space between the two cantilever arms is a 17 ft Gap the center 7 ft of the 17 ft Gap we'll need to Bear approximately 17,000 lb spread evenly from the front of the cantilever to the back of the cantilever over 5 ft. I will put support beams across these cantilever arms to support the load evenly
Thread 'What's the most likely cause for this carbon seal crack?'
We have a molded carbon graphite seal that is used in an inline axial piston, variable displacement hydraulic pump. One of our customers reported that, when using the “A” parts in the past, they only needed to replace them due to normal wear. However, after switching to our parts, the replacement cycle seems to be much shorter due to “broken” or “cracked” failures. This issue was identified after hydraulic fluid leakage was observed. According to their records, the same problem has occurred...
Back
Top