It is tangent, I drew it quickly, sorry.haruspex said:Not sure I understand the question. If there's no friction between stick and ball then the stick exerts a torque about the point of contact of ball with ground. That would seem to ensure the ball will roll, yet it says the stick 'rests'.
Your diagram is strange. The horizontal line for the floor should be tangent to the ball at its lowest point.
Wouldn't the friction between the ball and the ground prevent it from rolling? Either way, can't the ball be ignored since I'm looking at the forces on the stick? I assume the ball was only used to find the lever arm for the force of the stick on the ball (N in the picture).haruspex said:Not sure I understand the question. If there's no friction between stick and ball then the stick exerts a torque about the point of contact of ball with ground. That would seem to ensure the ball will roll, yet it says the stick 'rests'.
Your diagram is strange. The horizontal line for the floor should be tangent to the ball at its lowest point.
henry3369 said:It is tangent, I drew it quickly, sorry.
No. If it accelerates the force will be less because of the stick's inertia.CWatters said:Yes I think it's irrelevant if the ball moves. If it does then you can assume that the force you are being asked to calculate is the initial force just before the ball starts moving.
Yeah that is correct. I'm confused why it is 0.0892 + 0.103 though. Isn't 0.0892 the top half so the entire side of the triangle would be 0.0892 *2. I'm starting at my picture and I can't see where I've gone wrong.CWatters said:Yes I think it's irrelevant if the ball moves. If it does then you can assume that the force you are being asked to calculate is the initial force just before the ball starts moving.
Redraw it again. This error means your calculation includes "0.0892 * 2" which I think is incorrect. I believe it should be "0.0892 + 0.103"
Never mind, I see where the 0.103 comes from. Thanks!CWatters said:Yes I think it's irrelevant if the ball moves. If it does then you can assume that the force you are being asked to calculate is the initial force just before the ball starts moving.
Redraw it again. This error means your calculation includes "0.0892 * 2" which I think is incorrect. I believe it should be "0.0892 + 0.103"
No. It can prevent sliding, but not rolling.henry3369 said:Wouldn't the friction between the ball and the ground prevent it from rolling?
No. If the ball accelerates then so does the stick (rotationally), and the stick's acceleration implies a net torque on it.henry3369 said:Either way, can't the ball be ignored since I'm looking at the forces on the stick?
Quite so. But it doesn't ask for the horizontal component of the normal force. It asks for the horizontal component of the total force:henry3369 said:there is no component of the normal force pointing along the ground
The floor is rough and horizontal. The normal force is therefore vertical. What do we call the horizontal force from such a floor?henry3369 said:Find the horizontal and vertical component of the force exerted on the stick by the floor.
Torque is a measure of the force that causes an object to rotate around an axis. It is calculated by multiplying the force applied to an object by the distance from the axis of rotation.
When a stick is resting on a bowling ball, there is a force acting on the stick due to gravity. This force creates a torque on the ball, causing it to rotate around its axis.
The torque on a bowling ball depends on the force applied by the stick, the distance from the axis of rotation, and the angle at which the force is applied. Increasing any of these factors will increase the torque on the ball.
Torque is directly proportional to angular acceleration. This means that the more torque applied to an object, the more it will rotate or accelerate.
Torque is used in many real-life applications, such as car engines, bicycles, and construction equipment. It is also used in sports, such as bowling and baseball, to create rotational motion and increase the speed of an object.