Torques please explain it a little more.

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The discussion focuses on simplifying the torque equation T sin30.0° − w((L/2)cos30.0°) − w(Lcos30.0°) = 0 to T sin30.0° − (3w/2)cos30.0° = 0. Participants seek clarification on how the variable L can be factored out and eliminated from the equation. The conversion of the weight terms from w to (3w/2) is also questioned, indicating confusion over the algebraic manipulation involved. A request for a step-by-step explanation highlights the need for clearer understanding of the simplification process. Overall, the thread emphasizes the importance of grasping basic algebraic principles in torque calculations.
cary1234
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can you please explain why this

(TLsin30.0° − w((L/ 2)cos30.0°) − w(Lcos30.0°) = 0)



becomes this

T sin30.0° − (3w/ 2)cos30.0° = 0

i though i can do all the transpose and other stuff. but i can't figure that one.

i want to get the T.
please help me.
 
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I don't know what this about, but it seems simpel algebra: All terms are divisible
by L so you can factor it out, ant then you add the last two terms.
 
willem2 thanks for your response.
that is one of the example in my book.

can you please explain it a little bit more. maybe a step by step?
please.

how come that all the L are gone and the W are only 2 then it becomes 3. i will appreciate it very much.
 
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