Total work done on clay during Spring Compression

AI Thread Summary
The discussion revolves around calculating the total work done on a 4.63-kg ball of clay during its compression of a spring with a spring constant of 1610 N/m. The maximum compression of the spring was determined to be 0.50230 m. Initially, the user attempted to calculate the work done using the integral of the spring force but arrived at an incorrect value of -203.106 J. After reevaluating, the correct total work done was found to be -180.3 J, calculated using the formula W = Ks + Ub. The user successfully resolved their confusion regarding the calculation.
Koscher
Messages
21
Reaction score
0

Homework Statement



A 4.63-kg ball of clay is thrown downward from a height of 2.69 m with a speed of 5.01 m/s onto a spring with k = 1610 N/m. The clay compresses the spring a certain maximum amount before momentarily stopping.

b) Find the total work done on the clay during the spring's compression.

Homework Equations



Us=integral(-kx dx)

The Attempt at a Solution



From part of the question I found the maximum compression of the spring to be 0.50230 m, and I know that is correct.

I thought that the total amount of work done on something by the spring's compression was equal to the integral that is in the relevant equations section.

Therefore, that is what I did. I Us=integral(-kx dx) from 0 to 0.50230. The resulting answer was -203.106 J. But that is not correct, does anyone have some insight to what went wrong?
 
Physics news on Phys.org
Nevermind, i figured it out.

W = Ks + Ub

W=(-1/2)(1610)(0.502302) + (4.63)(9.81)(0.50230)

W= -180.3 J
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top