Tractive force for wheeled vehicle

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The discussion revolves around calculating the tractive force of a locomotive hauling a train up an incline and the drawbar pull between them. The tractive force is derived using the equation F = R + mgsinθ + ma, where the resistive force and incline angle are considered. The participants clarify that the same formula applies to both the locomotive and the train, but the drawbar pull should focus solely on the forces acting on the train. The drawbar pull can be determined by isolating the forces on the train, given that the acceleration and other forces are known. The conversation emphasizes the importance of correctly applying Newton's laws to solve the problem.
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Homework Statement


a locomotive of mass 20 tonnes hauls a train of mass 200 tonnes up an incline of 1 in 200. the resistive force for the locomotive and the train is 40 Newtons per tonne. the train accelerates from rest to 60km/h in 2km.determine;
a) the tractive force of the locomotive
b) the drawbar pull between the locomotive and the train

Homework Equations


F=R+mgsinθ+ma from the Newton's second law of motion

The Attempt at a Solution


part a
mass=20000kg
sinθ=0.005
R=800
s=2000m
u=0
v=16.67m/s2
a=0.069m/s2
by substituting the equation above F will be 3161N or 3.161KN
now in the second part is where am getting difficulty in solving how can it be approached please
 
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welcome to pf!

hi siludavid! welcome to pf! :smile:
siludavid said:
now in the second part is where am getting difficulty in solving how can it be approached please

(i haven't checked your figures)

the tractive force is found by using Ftotal = ma on the locomotive plus the train

the drawbar force is found by using Ftotal = ma on the train only :wink:
 
where will the angle of inclination and the resistive force be used in that case
 
siludavid said:
where will the angle of inclination and the resistive force be used in that case

uhh? :confused:

same in both cases …

your F = ma equation (in both cases) is parallel to the slope

(if you're not sure, write out the equations to show us)
 
according to me the tractive force minus the resistive force minus the resistive force due inclination which is mgsigθ because it always act on the opposite direction which will equal to ma that is;
F-R-mgsinθ=ma
therefore;
F=R+mgsinθ+ma
where R will be the resistive force together with mgsinθ
 
siludavid said:
F=R+mgsinθ+ma
where R will be the resistive force together with mgsinθ

yes :smile:

(same formula for both questions)
 
now my problem is the drawbar remember it connects the train and the locomotive, will you find the tractive force in both locomotive and the train then find the difference between the two to get the pull or what should you do to get the drawbar pull
 
siludavid said:
now my problem is the drawbar remember it connects the train and the locomotive, will you find the tractive force in both locomotive and the train then find the difference between the two to get the pull or what should you do to get the drawbar pull

consider only the forces on the train …

you know what the acceleration is, and you know all the forces except the drawbar force :wink:
 
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