(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known dataHi, I have been working on this problem for a while, and cannot figure it out. Heres the question.

An arrow is shot at an angle of theta = 45 degrees above the horizontal. The arrow hits a tree a horizontal distance D = 220m away, at the same height above the ground as it was shot. Use g = 9.8m/s^2 for the magnitude of the acceleration due to gravity

a.)Find t, the time that the arrow spends in the air.

b.)Suppose someone drops an apple from a vertical distance of 6.0 meters, directly above the point where the arrow hits the tree. How long after the arrow was shot should the apple be dropped, in order for the arrow to pierce the apple as the arrow hits the tree?

2. Relevant equations

Vx = Vcos(theda), x= Vt

3. The attempt at a solution

a.) a = 2x / t^2, 9.8 = 2(220cos45) / t^2, t = 5.6

5.6 is not the right answer. Thanks for your time.

**Physics Forums - The Fusion of Science and Community**

# Trajectory Motion

Have something to add?

- Similar discussions for: Trajectory Motion

Loading...

**Physics Forums - The Fusion of Science and Community**