Transfer function-leading and lagging

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The transfer function G(jw) = 1/(1-j) indicates that the output to input amplitude ratio is 1/sqrt(2), with the output leading the input by 45 degrees. The confusion arises from the interpretation of jw as the input, while the right-hand side represents the output. The magnitude of G(jw) is calculated using the formula |G(jw)| = sqrt(Re^2 + Im^2), where Re is the real part and Im is the imaginary part. The phase relationship is determined using the arctan function, taking care to consider the signs of the real and imaginary components. Understanding these relationships is crucial for accurate analysis of the transfer function.
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If we have the transfer function:
G(jw)=1/(1-j) where j=imaginary number

What is the output to input amplitude ratio and the phase relationship.

I'm confused about which one is the output and which is the input. I thought jw, the argument, is the input and everything on the right hand side is the output?

If so, this is not getting my the right answers that output to input amplitude ratio=1/sqrt(2) and that output leads input by 45 degrees.
 
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pyroknife said:
If we have the transfer function:
G(jw)=1/(1-j) where j=imaginary number

What is the output to input amplitude ratio and the phase relationship.

I'm confused about which one is the output and which is the input. I thought jw, the argument, is the input and everything on the right hand side is the output?

If so, this is not getting my the right answers that output to input amplitude ratio=1/sqrt(2) and that output leads input by 45 degrees.

G(jw) = output/input.

The magnitude of G(jw) = |G(jw)| = sqrt(Re^2 + Im^2)
where Re = "real part" and I am = "imaginary part".

The phase of output/input is arc tan(Im/Re). Be careful to preserve the sign of the numerator and the denominator. Arc tan(-b/a) is not the same angle as arctan(b/-a).
 
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