Transformer Winding Calculations: Primary to Secondary Current and Voltage

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A transformer with a 120-turn primary winding and an 1800-turn secondary winding has a primary current of 10A and a voltage of 550V. The power in the primary coil is calculated as 5500W, which must equal the power in the secondary coil. Using the turns ratio, the potential difference across the secondary coil is determined to be 8250V. Consequently, the current in the secondary coil is calculated to be approximately 0.67A. This demonstrates the principles of energy conservation and transformer operation.
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Please can someone help me with his question

A transformer has a 120-turn primary winding and an 1800-turn secondary winding. A current of 10A flows in the primary winding when the potential difference of 550V is placed across it. Find the current in the secondary winding and the potential difference across it.

thank you
 
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Where would you start with this?

It's a pretty basic conservation of energy problem once you know where to go
 
so far i have

120 = 550 =
1800 33 10

i got the 33 through the ration of 120/800
 
P=IV in primary coil

10x550=5500W

hence 5500W in secondary coil

pd across secondary coil = 550/120 x 1800 = 8250V

current across secondary coil = 5500/8250 = 0.67A (2sf)
 
thank you :)
 
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