Transition from one dielectric medium to another medium

AI Thread Summary
A plane electromagnetic wave with a frequency of 5×10^14 Hz and amplitude of 103 V/m is transitioning between two dielectric media with dielectric constants of 1.69 and 2.25. The amplitude ratio of the transmitted wave to the incident wave is influenced by the reflection and the continuity of electric and magnetic fields at the boundary. The correct calculation involves relating the dielectric constants to the indices of refraction, leading to a ratio of approximately 0.93 for the electric field amplitudes. There was some confusion regarding the application of these concepts, particularly in distinguishing between electric and magnetic field amplitudes. Ultimately, the discussion clarified the importance of using the correct equations and understanding the relationship between dielectric constants and indices of refraction.
phoenix95
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Homework Statement


A plane electromagnetic wave of frequency 5×1014 Hz and amplitude 103 V/m, traveling in a
homogeneous dielectric medium of dielectric constant 1.69, is incident normally at the interface
with a second dielectric medium of dielectric constant 2.25. The ratio of the amplitude of the
transmitted wave to that of the incident wave is ___________.

Homework Equations



The Attempt at a Solution


It should be 1 right? I mean passing from one dielectric medium to another would result in the change of phase velocity but not the amplitude??
 
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You should also consider reflection.
 
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DrDu said:
You should also consider reflection.
Would you please explain a little bit? I don't know how to apply that concept...
 
If the media are transparent, then the sum of the reflected and transmitted intensity must equal the incident intensity. The relative intensity of the transmitted and reflected intensity is dictated by the continuity of electric and magnetic fields at the boundary. Probably you were talking about this in class?
 
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DrDu said:
If the media are transparent, then the sum of the reflected and transmitted intensity must equal the incident intensity. The relative intensity of the transmitted and reflected intensity is dictated by the continuity of electric and magnetic fields at the boundary. Probably you were talking about this in class?
No, this question is from one of the entrance examinations... I tried searching in the internet but I couldn't find any reasonable explanations...
 
so the answer would be 0.857... Thanks a lot... The information was very useful...:smile:
 
phoenix95 said:
so the answer would be 0.857...
I don't believe this is the correct answer.

Equation (1227) of the link gives Et (but there is a misprint on the right of the equation where Et should be Ei).

Note that this equation is in terms of the indices of refraction of the materials, not the dielectric constants.

I guess you have to assume that the question is concerned with the electric field amplitudes and not the magnetic field amplitudes.
 
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The index of refraction and the relative dielectric constant are related as ##n=\sqrt{\epsilon_r}##. So n1=1.3 and n2=1.5 giving for the ratio of the transmitted to the incident electric field amplitude: 2n1/(n1+n2)=2.6/(1.3+1.5)=0.93.
 
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