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For potential well problem for well with potential which is zero in the interval ##[0,a]## and infinite outside we get ##\psi_n(x)=\sqrt{\frac{2}{a}}\sin \frac{n\pi x}{a}##. If I want to get this result for well with potential which is zero in the interval ##[-\frac{a}{2},\frac{a}{2}]## and infinite outside we must do some translation. May I say that the wave function for this problem is

[tex]\psi_n(x-\frac{a}{2})?[/tex]

[tex]\psi_n(x-\frac{a}{2})?[/tex]

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