Translational Equilibruim problem

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The discussion revolves around solving a translational equilibrium problem involving two blocks connected by a string, with one block on a 42-degree incline and the other hanging. The mass of the block on the incline is 6.7 kg, and the goal is to find the mass of the hanging block that maintains equilibrium. Participants clarify the definitions of various tension components in the system, emphasizing that there is a single tension throughout the string due to the massless string and frictionless pulley assumption. To achieve equilibrium, the net force on each block must equal zero, leading to the conclusion that the tension needs to be calculated to prevent the inclined block from sliding. The next steps involve determining the required tension and the corresponding mass of the hanging block.
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Problem-
Two blocks are connected by a string. The smooth inclined surface makes an angle of 42 with the horizontal, and the block on the incline has a mass of 6.7kg. Find the mass of the hanging block that will cause the system to be in equilibruim.

Answer-
so far i have gooten this:
t1x= -T1 Cos(42)
T2x= 0
T1y= T2 sin(42)
T2y=mg ?

What do I do next? please help
 
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Since you haven't told us what "T1", "t1x", "T1y", "T2", or "T2y" mean, it's impossible to tell what you have done or what you should do next.
 
"T1x"= is the tension created by the first block horizontally

"T1y",= is the tension created by the first block vericallly

"T2x", = is the tension created by the second block horizonal

"T2y"=is the tension created by the second block verically
 
Assuming the usual massless string over a frictionless pulley, there is only one tension throughout the string. Call it T. Now what must that tension be to prevent the mass on the incline from sliding down? Then figure what the hanging mass must be to create that tension.

For equilibrium, the net force on each mass must be zero.
 
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