Translational Momentum of a particle

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Suppose that your mass is 80 kg. How fast would you have to run to have the same translational momentum as a 1600 kg car moving at 1.2 km/h? I happen to know the answer is 24 km/hr. But, how do I get to this answer? What are the steps? Could someone solve it out and show me how they got it? Thanks a million!
 
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Momentum, which we denote by p, is simply the product of the mass and the velocity: p=mv. So since you know the mass and velocity of the car you can calculate its momentum and since you know what your mass is you can calculate what your velocity needs to be in order to have that same momentum.
 
The car's momentum is 1600*1.2 kg-km/hr? That being 1920. What would the units be?
Now my momentum is 80*Vu kg-km/hr where Vu is your velocity?
Where do I go from here?
 
Equate the two and solve for Vu. Momentum doesn't have a special unit in the SI system, it's usually just written as kg*m/s or sometimes N*s (the two are equivalent).
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
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