I Transmission and absorbance of materials in the deep UV

AI Thread Summary
Materials with high transmittance often begin to absorb in the deep UV due to the increased energy of light quanta, which can excite more electrons. This absorption occurs at specific wavelengths where the material's electronic structure allows for transitions, leading to different absorption edges among materials. The variation in absorption edges is attributed to differences in electronic band structures and the energy levels of electrons in different materials. Interestingly, transmittance can improve again at x-ray wavelengths due to changes in electron interactions. Understanding these phenomena is crucial for applications in optics and materials science.
DariusP
Messages
50
Reaction score
3
I wanted to ask - why do some materials with very high transmittance inevitably start to absorb in deep UV? Is there an explanation?
 
Physics news on Phys.org
Don't worry. They get their transmittance back when you get to x-rays. :smile:

The mo`re energy the light quantum has, the more electrons are available for it to excite.
 
Vanadium 50 said:
Don't worry. They get their transmittance back when you get to x-rays. :smile:

The mo`re energy the light quantum has, the more electrons are available for it to excite.
But why does it start to suddenly absorb in deep UV? Any explanation for the edge and why different materials have different absorption edges?
 
Thread 'Gauss' law seems to imply instantaneous electric field'

Thread 'Gauss' law seems to imply instantaneous electric field'

Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire. We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges. By using the Lorenz gauge condition: $$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$ we find the following retarded solutions to the Maxwell equations If we assume that...
View full post »

Thread 'Do electron density waves accompany EM waves in coaxial cables?'

Maxwell’s equations imply the following wave equation for the electric field $$\nabla^2\mathbf{E}-\frac{1}{c^2}\frac{\partial^2\mathbf{E}}{\partial t^2} = \frac{1}{\varepsilon_0}\nabla\rho+\mu_0\frac{\partial\mathbf J}{\partial t}.\tag{1}$$ I wonder if eqn.##(1)## can be split into the following transverse part $$\nabla^2\mathbf{E}_T-\frac{1}{c^2}\frac{\partial^2\mathbf{E}_T}{\partial t^2} = \mu_0\frac{\partial\mathbf{J}_T}{\partial t}\tag{2}$$ and longitudinal part...
View full post »

Similar threads

B UV detection by fluorescent goggles
Replies
6
Views
2K
A Why people say we can't "feel" UV?
Replies
6
Views
1K
I What power rating do UV-A Tubes have? (tanning salons)
Replies
10
Views
1K
I Interaction of EM radiation with Glass
Replies
14
Views
2K
I Absorbance of a finite waveband
Replies
6
Views
1K
I How does the electron come back down in energy level after absorbing a photon?
Replies
37
Views
5K
I Colorless Compounds and electromagnetic radiation
Replies
19
Views
3K
Opaque Materials & UV Resistance: Advice for Buying Curtains
Replies
4
Views
2K
I Magnetic Component Permeability vs Frequency Loss
Replies
21
Views
2K
A A couple of long questions on positivity bounds for UV-complete EFTs
Replies
4
Views
833

Hot Threads

Recent Insights

Back
Top