Transmission line approimation

likephysics
Messages
638
Reaction score
4
Transmission line approximation

Homework Statement


In the derivation of the approximate formulas of \gamma and Z0 for low loss lines, all terms containing the second and higher order powers of R/wL and G/wC were neglected in comparison with unity. (R/wL<<1 and G/wC<<1)
gamma=jw*sqrt(LC)*sqrt(1+R/jwL)*sqrt (1+G/jwC)
approximated to
gamma = jw*sqrt(LC)*(1+R/2jwL)*sqrt(1+G/2jwC)

gamma is the propagation constant which is equal to alpha+j beta

At lower frequencies, better approximation may be required. find new formulas for \gamma and Z0 for low loss lines that retain terms containing (R/wL)^2 and (G/wL)^2


Homework Equations


Required result is
alpha = sqrt(LC/2)*(R/L+G/C)*[1-(1/8w^2)*(R/L-G/C)^2]
beta = w*sqrt (LC)*[1+(1/8w^2)*(R/L-G/C)^2]


The Attempt at a Solution


I tried expanding the term
sqrt(1+R/jwL) using square root expansion :
1+(1/2)*R/jwL-(1/8)*(R/jwL)^2
did the same for sqrt (1+G/jwC)
I am unable to get the desired result. Any help.
FYI, this is prob 9.7 in cheng.
 
Last edited:
Physics news on Phys.org


likephysics said:
I tried expanding the term
sqrt(1+R/jwL) using square root expansion :
1+(1/2)*R/jwL-(1/8)*(R/jwL)^2
did the same for sqrt (1+G/jwC)

That looks fine to me...what do you get when you multiply everything out?
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top