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physnoob
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Homework Statement
When mass M is tied to the bottom of a long, thin wire suspended from the ceiling, the wire's second-harmonic frequency is 200 Hz. Adding an additional 1kg to the hanging mass increases the second-harmonic frequency to 245 Hz. What is M?
f[tex]_{2}[/tex] = 200hz, m = M
f[tex]_{2}[/tex] = 245hz, m = M+1
g = 9.8m/s
Homework Equations
f=v/L, v = [tex]\sqrt{T/u}[/tex]
The Attempt at a Solution
not sure where to start the problem
please help!
any help is greatly appreciated!