Does y(x,t) Satisfy the One-Dimensional Wave Equation?

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The discussion centers on verifying if the given transverse traveling wave equation y(x,t) = 0.6exp(2x-5t)cos(5t-2x) satisfies the one-dimensional wave equation. Participants are clarifying the correct interpretation of the wave function, particularly the role of the amplitude A and the confusion arising from the terms involving x and t. The wave equation to be satisfied is defined as ∂²y/∂x² = (1/v²)∂²y/∂t². The conversation emphasizes the need to differentiate y(x,t) twice with respect to both x and t to confirm compliance with the wave equation. Ultimately, the focus is on understanding the mathematical relationships within the wave function.
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A transverse traveling wave is described by

y(x,t) = 0.6exp(2x-5t)cos(5t-2x)​

for x and y measured in centimeters and t in seconds.
Show that y(x,t) satisfies the one-dimensional wave equation.

I think that I have to show that y(x,t)=f(x+/-vt) where f is a funtion of x and t. Am I correct in calling A=0.6exp(2x-5t) or is it A=cos(5t-2x), because the reversal of the x and t values in the second case is confusing me. Any pointers on where to begin.
 
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The one-dimensional wave equation is \frac{\partial^2 y}{\partial x^2} = \frac{1}{v^2}\frac{\partial^2y}{\partial t^2}.

See how you get on, knowing this.
 
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